All categories

3 years ago

What is the GCF of 15 and 20

Mathematics

1 answer:

valina [46]3 years ago

6 0

Answer: 5

Step-by-step explanation: To find the (GCF) or greatest common factor of 15 and 20, begin by finding all of the factors of 3.

Since 15 ÷ 1 is 15, this means that 1 and 15 are factors.

Since 15 ÷ 3 gives us 5, this means that 3 and 5 are factors.

Also, 15 ÷ 5 and 15 ÷ 15 would be factors, but we don't list repeat factors.

Next, we find all of the factors of 20.

Since 20 ÷ 1 is 20, we know that 20 and 1 are factors.

Since 20 ÷ 2 is 10, we know that 10 and 2 are factors.

Since 20 ÷ 4 is 5, we know that 5 and 4 are factors.

Now we look for the largest factor that is shared by the two lists which is 5.

Therefore, the greatest common factor of 15 and 20 is 5.

You might be interested in

How do i write the difference of a number x and 2 is 7 as an equation

HACTEHA [7]

You can quiet literally write the question as it is.

The difference of a number x and 2 is 7.

The difference of a number x and 2 can be written as x-2

is can be written as equal or =

This statement can be translated as x-2=7.

It is as simple as that!

5 0

3 years ago

Rentite in simplest terms: - 10(9c – 7c+8) - 80

zhannawk [14.2K]

Answer:

-20c-160

Step-by-step explanation:

-10(9c-7c+8)-80

-10(2c+8)-80

-20c-80-80

-20c-160

8 0

3 years ago

Read 2 more answers

In algebra, we transfer these same skills to expressions involving variables. what elementary skills have you used so far in thi

kirza4 [7]

Input a picture possibly? then i’ll be able to answer…

3 0

2 years ago

Can a chord also be classified as a radius? Explain your answer.

aalyn [17]

No
A chord is a straight sediment that joins two points of the circumference. The radius goes from the center of the circle, which is not on the radius.

6 0

4 years ago

Help I’ll do anything just help

Gnom [1K]

Answer:

$1) {n}^{2} - 81 \\ (n - 9)(n + 9)$

$2) \: \: {a}^{2} - 121 \\ (a - 11)(a + 11)$

$3) \: \: {n}^{2} - 16 \\ (n - 4)(n + 4)$

$4) \: \: 9 {x}^{2} - 144 \\ {3}^{2} {x}^{2} - {12}^{2} \\ (3x - 12)(3x + 12)$

$5) \: 2 {x}^{2} - 9 \\ (2x - 3)(x + 3)$

$6) \: \: 4 {w}^{2} - 9 \\ {2}^{2} {w}^{2} - {3}^{2} \\ (2w + 3)(2w - 3)$

$7) \: \: 4 {n}^{2} - 1 \\ {2}^{2} {n}^{2} - {1}^{2} \\ (2n + 1)(2n - 1)$

$8) \: \: 1 - 16 {x}^{2} \\ {1}^{2} - {4}^{2} {x}^{2} \\ (1 - 4x)(1 + 4x)$

$9) \: \: {x}^{2} - {y}^{2} \\ (x - y)(x + y)$

$10) \: \: 9 - {c}^{2} \\ {3}^{2} - {c}^{2} \\ (3 - c)(3 + c)$

$11) \: \: {n}^{2} - 25 \\ {n}^{2} - {5}^{2} \\ (n + 5)(n - 5)$

$13)49 - 4 {a}^{2} \\ {7}^{2} - {2}^{2} {a}^{2} \\ (7 - 2a)(7 + 2a)$

$14) {a}^{2} {b}^{2} - {c}^{4} \\ (ab - {c}^{2} )(ab + {c}^{2} )$

$15) \: \: 4 {x}^{2} {y}^{2} - 9 {z}^{2} \\ {2}^{2} {x}^{2} {y}^{2} - {3}^{2} {z}^{2} \\ (2xy - 3z)(2xy + 3z)$

hope this helps

sorry, I don't know how solve the 12th one.

thanks.

7 0

3 years ago