Sixty-five elements were randomly sampled from a population that has 200 elements. the sample mean is 180 with a variance of 135
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Answer:
Two mittens and seven gloves
Step-by-step explanation:
I presume you are asking how many mittens and how many gloves Beth should knit to produce the most profit.
Let x = the number of mittens and
Let y = the number of gloves
1. Summarize the information in a table
2. List the constraints
(a) Beth can't make a negative number of mittens, so
x ≥ 0.
(b) Neither can she make a negative number of gloves, so
y ≥ 0.
(c) The total number of minutes on Machine A cannot exceed 32, so
2x + 4y ≤ 32.
(d) The total number of minutes on Machine B cannot exceed 18, so
2x + 2y ≤ 18.
(e) The total number of minutes on Machine C cannot exceed 24, so
4x + y ≤ 24.
3. Write an equation for the profit
P = 8.00x + 10.00y
4. Graph the constraints to identify the feasible region
See the figure below. The feasible region is the dark green area where all three regions overlap.
5. Determine the points of intersection between the constraints
(i) Constraints (c) and (d)
The lines intersect at (2,7).
(ii) Constraints (c) and (e)
The lines intersect at (27/7,32/7).
(iii) Constraints (d) and (e)
The lines intersect at (5,4).
6. Determine the x- and y-intercepts of the feasible region
(i) x-intercept
The x-intercept is at (6,0).
(ii) y-intercept
The y-intercept is at (0,8).
The five black dots are the vertices of the polygon that represents the feasible region.
7. Calculate the maximum profit
Calculate the profit at each of the vertices.
(i) At (0,0)
P = 8.00x + 10.00y = 8.00(0) + 10.00(0) = 0 + 0 = $0
(ii) At (2,7)
P = 8.00(2) + 10.00(7) = 16 + 70 = $86
(iii) At (5,4)
P = 8.00(5) + 10.00(4) = 40 + 40 = $80
(iv) At (6,0)
P = 8.00(6) + 10.00(0) = 48 + 0 = $48
The maximum profit occurs at (2,7)
Thus, Beth should knit two mittens and seven gloves.
