The zeroes of <span>f(x) = x^5-12x^2+32x can be found by factoring,
</span><span>f(x) = x^5-12x^2+32x=(x-8)(x-4)
By the zero product theorem, (x-8)=0 or (x-4)=0 which means
x=8 or x=4.
So the zeroes of f(x) are S={4,8}</span>
Answer: lppkoijhuytfrdeswasdxcvbn
Step-by-step explanation:
Answer: -16
Step-by-step explanation:
-3 is less than -2 so use the first one
Plug into equation
5(-3)-1
-15-1= -16
The answer answer is 42. 8
Answer:
In a class of 40 students, 20% are females. How many males are in the class?
ANSWER
= 32
