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alexgriva [62]
3 years ago
7

Find the area of ths-figure

Mathematics
1 answer:
Ugo [173]3 years ago
3 0

Answer:

<u>202 square inches</u>

Step-by-step explanation:

We can break this shape down into two rectangles, one with the dimensions of 13in by 4in and the other by 15in and 10in. Now we can find the area of both shapes by multiplying the sides together so the 13in by 4in shape has the area of 52 square inches and the 15in by 10in shape has the area of 150 square inches. Now, add the two areas together and the total area of the whole shape is 202 square inches.

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I need help because I totally forgot about it
Verizon [17]
Right triangle has one degree = 45 so it's isosceles right triangle.
let y = hypotenuse of small isosceles right triangle 

y^2 = 7^2 + 7^2
y^2 = 49 + 49
y^2 = 98

so 
x^2 = 98 + 98
x^2 = 196
x = 98

answer
x = 98




5 0
3 years ago
The quotient of a number and -7, decreased by 2, is 10
Mars2501 [29]

Answer:

wouldnt it be -9

Step-by-step explanation:

beacuse negitive 7-2 is negitive 9 bc negitive plus a negitive is a negitive ?? right

3 0
3 years ago
Solve for m: 329 + 5.75m = 363.50
mihalych1998 [28]

Answer:

m = 6

Step-by-step explanation:

5.75 x 6 = 34.5

329 + 34.5 = 363.50

5 0
3 years ago
The breaking strengths of cables produced by a certain manufacturer have a mean, , of pounds, and a standard deviation of pounds
olchik [2.2K]

The question is incomplete. The complete question is :

The breaking strengths of cables produced by a certain manufacturer have a mean of 1900 pounds, and a standard deviation of 65 pounds. It is claimed that an improvement in the manufacturing process has increased the mean breaking strength. To evaluate this claim, 150 newly manufactured cables are randomly chosen and tested, and their mean breaking strength is found to be 1902 pounds. Assume that the population is normally distributed. Can we support, at the 0.01 level of significance, the claim that the mean breaking strength has increased?

Solution :

Given data :

Mean, μ = 1900

Standard deviation, σ = 65

Sample size, n = 150

Sample mean, $\overline x$ = 1902

Level of significance = 0.01

The hypothesis are :

$H_0 : \mu = 1900$

$H_1 : \mu > 1900$

Test statics :

We use the z test as the sample size is large and we know the population standard deviation.

$z=\frac{\overline x - \mu}{\sigma / \sqrt{n}}$

$z=\frac{1902-1900}{65 / \sqrt{150}}$

$z=\frac{2}{5.30723}$

$z=0.38$

Finding the p-value:

P-value = P(Z > z)

             = P(Z > 0.38)

             = 1 - P(Z < 0.38)

From the z table. we get

P(Z < 0.38) = 0.6480

Therefore,

P-value = 1 - P(Z < 0.38)

            = 1 - 0.6480

             = 0.3520

Decision :

If the p value is less than 0.01, then we reject the H_0, otherwise we fail to reject  H_0.

Since the value of p = 0.3520 > 0.01, the level of significance, then we fail to reject  H_0.

Conclusion :

At a significance level of 0.01, we have no sufficient evidence to support that the mean breaking strength has increased.

4 0
3 years ago
PLS HELP ASAP PLS PLS PLS
Amanda [17]

0=0

Step-by-step explanation:

4(×+3)=4x+12

4x+12=4x+12

Subtract 12 from both sides of the equation

4x+12-12=4x+12-12

simplify

4x=4x

Subtract 4x from both sides of the equation

4x-4x= 4x-4x

Simplify and combine like terms

0=0

8 0
2 years ago
Read 2 more answers
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