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3 years ago

15

How Many Solutions? 3x - 7 = 3(x - 3) + 2 No Solution One Solution Infinite Solution

1 answer:

prisoha [69]3 years ago

3 0

Answer:

Infinite Solutions

Step-by-step explanation:

3x-7=3x(x-3)+2

3x-7=3x-9+2 - Distributive Property

3x-7=3x-7 - adding the right side together

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The mass of an ant is 1/10 of the load, which it can carry in one try. What is the mass of the ant, if in one time it can carry

Viefleur [7K]

If you call $m$ the mass of the ant and $l$ the load, we have the equation

$m = \cfrac{l}{10}$

In fact, the mass of the ant is one tenth of the load, which is exactly what this equation states.

Since we are given the load, we simply need to plug its value in the equation to deduce the mass of the ant:

$m = \cfrac{\frac{7}{250}}{10} = \cfrac{7}{250}\cdot\cfrac{1}{10} = \cfrac{7}{2500}$

8 0

3 years ago

Suppose I have an urn with 9 balls: 4 green, 3 yellow and 2 white ones. I draw a ball from the urn repeatedly with replacement.

Mrrafil [7]

Answer:

$E(X_n)=\frac{2(n-1)}{27}$

$E(y)=\frac{14}{9}$

Step-by-step explanation:

From the question we are told that:

Sample size n=9

Number of Green $g=4$

Number of yellow $y=4$

Number of white $w=4$

Probability of Green Followed by yellow P(GY) ball

$P(GY)=\frac{4}{9}*\frac{3}{9}$

$P(GY)=\frac{4}{27}$

Generally the equations for when n is even is mathematically given by

$Probability of success P(S)=\frac{4}{27}$

$Probability of Failure P(F)=\frac{27-4}{27}$

$Probability of Failure P(F)=\frac{23}{27}$

Therefore

$E(X_n)=\frac{n}{2}*P$

$E(X_n)=\frac{n}{2}*\frac{4}{27}$

$E(X_n)=\frac{2n}{27}$

Generally the equations for when n is odd is mathematically given by

$\frac{n-1}{2}$

$E(X_n)=\frac{n-1}{2}*\frac{4}{27}$

$E(X_n)=\frac{2(n-1)}{27}$

b)

Probability of drawing white ball

$P(w)=\frac{2}{9}$

Therefore

$E(w)=\frac{1}{p}$

$E(w)=\frac{1}{\frac{2}{9}}$

$E(w)=\frac{9}{2}$

Therefore

$E(y)=[E(w)-1]\frac{4}{9}$

$E(y)=[\frac{9}{2}-1]\frac{4}{9}$

$E(y)=\frac{14}{9}$

5 0

3 years ago

If ON = MN, find MN.<br> A 4<br> B. 5<br> C. 4 square root 2<br> D. 4 square root 30

elena-14-01-66 [18.8K]

Answer:

c

Step-by-step explanation:

ON=MN, so triangle onm is a right isosclese triangle, so ON=NM=4 square root 2

4 0

3 years ago

Read 2 more answers

56 divided by 7 jdjcjdjdjdjfjjfhfjfhfjfhfufgdjssgjsjshsjwiwh

mrs_skeptik [129]

Its 8.

_08___
7 / 56
56
-----------------
0 <--- Leftover

So the answer is 8! Hope it helps! :D

6 0

3 years ago

Match the solid figure to the appropriate formula.

AlekseyPX

1. $L \cdot A=\pi r l$ - Cone

2. $V=\frac{4}{3} \pi r^{3}$ - Sphere

3. $T \cdot A=2 \pi r h+2 \pi r^{2}$ - Cylinder

4. $V=\frac{1}{3} B h$ - Pyramid

5. $L . A=p h$ - Prism

Solution:

1. $L \cdot A=\pi r l$

Lateral surface area of cone = $\pi r l$

where r is the radius of the cone and l is the slant height of the cone.

2. $V=\frac{4}{3} \pi r^{3}$

Volume of sphere = $\frac{4}{3} \pi r^{3}$

where r is the radius of the sphere.

3. $T \cdot A=2 \pi r h+2 \pi r^{2}$

Total surface area of cylinder = $2 \pi r h+2 \pi r^{2}$

where r is the radius of the cylinder and h is the height of the cylinder.

4. $V=\frac{1}{3} B h$

Volume of pyramid = $\frac{1}{3} B h$

where B is the base area of the pyramid and h is the height of the pyramid.

5. $L . A=p h$

Lateral surface area of prism = $p h$

where p is the perimeter of the base and h is the height of the prism.

4 0

2 years ago