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hram777 [196]
3 years ago
15

How Many Solutions? 3x - 7 = 3(x - 3) + 2 No Solution One Solution Infinite Solution

Mathematics
1 answer:
prisoha [69]3 years ago
3 0

Answer:

Infinite Solutions

Step-by-step explanation:

3x-7=3x(x-3)+2

3x-7=3x-9+2 - Distributive Property

3x-7=3x-7 - adding the right side together

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Here 1 more than BIG PRIZE
Firlakuza [10]
Hey there! :D

Use the distributive property.

a(b+c)= ab+ac

6(9x+2)+2x

54x+12+2x

56x+ 12 <== equivalent expression

I hope this helps!
~kaikers
4 0
3 years ago
Please help with areas
Softa [21]

Answer:

Step-by-step explanation:

7) The formula for determining the area of a parallelogram is expressed as

Area = base × height.

Length of base = Area/height

Therefore,

Length of base = 7/2 = 3.5 feet

8) The formula for determining the area of a trapezoid is expressed as

Area = 1/2(a + b)h

Where

a and b are the length of the bases

h is the height. Therefore

21 = 1/2(2 + 4)h

21 = 3h

h = 21/3 = 7 inches

9) Area = base × height.

Height = Area/Length of base

Height = 28/14 = 2 inches

10) a and b are 10 inches each.

Area = 1/2(a + b)h

Therefore,

35 = 1/2(10 + 10)h

35 = 10h

h = 35/10

h = 3 inches

7 0
3 years ago
The amount of a chemical solution is measured to be 2 liters.
Dafna1 [17]
<span>2 liters" only shows one significant figure. This "2 liters" can be anything from 1.9 liters to 2.1 liters. Actually, to be more strictly correct, the 2 liters can be between 1.5 liters and 2.4 liters. Either of these bounds would be 2 to the nearest ONE's place. 

The biggest percent error would be between 2 and 1.5, which is a volume error of 0.5 liters. 

Thus: (0.5/2)*100=25%  C: is your Answer</span>
3 0
3 years ago
What is the slope of the line? y - 4= -7(x-6) Choose 1 answer: 1 А. 7 4. B 7 --7 2 3​
givi [52]

Step-by-step explanation:

the slope is always the factor of x.

in slope intercept form, as well as here in point slope form.

the important thing is that the y term is just brought to a simple positive y form (and not cy with c is different than 1).

and then, what you see on the other side as factor is x is the slope.

here : -7

the other numbers in the equating are irrelevant for the slope. they determine the "offset" of the line from (0, 0).

3 0
2 years ago
Etermine two pairs of polar coordinates for the point (2, -2) with 0° ≤ θ &lt; 360°.
Jet001 [13]

To convert from rectangular to polar we will use these 2 formulas:

r^2=x^2+y^2 and

tan\theta=\frac{y}{x}.

The r value found serves as the first coordinate in our polar coordinate, and the angle serves as the second coordinate of the pair. We are told to find 2. Since the r value will always be the same (it's the length of the hypotenuse created in the right triangle we form when determining our angle theta), the angle is what is going to be different in our coordinate pairs. We use the x and y coordinates from the given rectangular coordinate to solve for the r in both our coordinate pairs.

r^2=2^2+ -2^2 which gives us an r value of 2\sqrt{2}. That's r for both coordinate pairs. Now we move to the angle. Setting up according to our formula we have

tan\theta =\frac{-2}{2} =-1.

This asks the question "what angle(s) has/have a tangent of -1?". That's what we have to find out! Since the tangent ratio is y/x AND since it is negative, it is going to lie in a quadrant where x is negative and y is positive, AND where x is positive and y is negative. Those quadrants are 2 and 4. In QII, x is negative so the tangent ratio is negative here; in QIV, y is negative so the tangent ratio is negative here as well. Now, if we type inverse tangent of -1 into our calculators in degree mode, we get that the angle that has a tangent of -1 is -45. Measured from the positive x axis, -45 does in fact go into the fourth quadrant. However, since the inverse tangent of -1 is -45, we also have a 45 degree angle in the second quadrant. Those are reference angles, mind you. A 45 degree angle in QII has a coterminal angle of 135 degree; a 45 degree angle in QIV has a coterminal angle of 315. If you don't understand that, go back to your lesson on reference angles and coterminal angles to see what those are. So our polar coordinates for that rectangular coordinate are

(2\sqrt{2},135) and

(2\sqrt{2},315)

8 0
3 years ago
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