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3 years ago

TIMED TEST PLEASE HELP

2 answers:

7 0

1. The cost for the 6% loan total is 375.76*48=18036.48, and for the 8% loan is 390.61*48= 18749.28. So, the benefit would be (subtract these) 712.80 to get the 6% loan over the 8% loan.

2. I am going to assume that there is an extra 7 in the 2777.90. One year, she will pay 277.90*12=3334.80. Over 2 years she will pay 152.69*24=3664.56. The benefit would be (subtract) $329.76.

xxMikexx [17]3 years ago

6 0

1 ) first offer
total payments
375.76×12×4
=18,036.48
Interest paid
18,036.48−16,000
=2,036.48
Second offer
Total payments
390.61×12×4
=18,749.28
Interest paid
18,749.28−16,000
=2,749.28
Larry will save of taking 6% loan
2,749.28−2,036.48=712.8. .answer

2) credit card 1
Total payments
277.09×12
=3,325.08
Interest paid
3,325.08−3,000
=325.08
Credit card 2
Total payments
152.69×12×2
=3,664.56
Interest paid
3,664.56−3,000
=664.56
Susan will save
664.56−325.08
=339.48...answer

Hope it helps!

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Find the percent of each number 3.5% of $1,200

barxatty [35]

Answer: 38.19

Step-by-step explanation: Well I like to find 1% first, so I would do 1,200/100. This equals 10.91.

But now seeing as we want 3.5%, we would multiply 10.91 by 3.5. This would give us 38.19 (or 38.18 if you don't round up)

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3 years ago

3.) A linear function passes through the points (0, 2) and (-4,0).

kotegsom [21]

Answer:

Step-by-step explanation:

The x-intercept is where y is 0.

The y-intercept is where x is 0.

The x-intercept would be (-4, 0) and the y-intercept (0, 2)

Using the slope formula, (y2-y1/x2-x1), we can find the slope which is 1/2.

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3 years ago

According to the U.S. Census Bureau, 11% of children in the United States lived with at least one grandparent in 2009 (USA TODAY

wel

Answer:

The pvalue of the test is 0.0001 < 0.02, which means that we reject the null hypothesis and accept the alternate hypohteis that the proportion of all children in the United States who currently live with at least one grandparent is higher than 11%.

Step-by-step explanation:

Proportion of all children in the United States who currently live with at least one grandparent is higher than 11%

This means that the null hypothesis is:

$H_0: p = 0.11$

And the alternate hypothesis is:

$H_a: p > 0.11$

The test statistic is:

$z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}$

In which X is the sample mean, $\mu$ is the value tested at the null hypothesis, $\sigma$ is the standard deviation and n is the size of the sample.

0.11 is tested at the null hypothesis:

This means that $\mu = 0.11, \sigma = \sqrt{0.11*0.89}$

Suppose that in a recent sample of 1550 children, 214 were found to be living with at least one grandparent.

This means that:

$n = 1550, X = \frac{214}{1550} = 0.1381$

Value of the test statistic:

$z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}$

$z = \frac{0.1381 - 0.11}{\frac{\sqrt{0.11*0.89}}{\sqrt{1550}}}$

$z = 3.54$

Pvalue of the test and decision:

This is the probability of finding a sample proportion above 0.1381, which is 1 subtracted by the pvalue of Z = 3.54.

$z = 3.54$ has a pvalue of 0.9999

1 - 0.9999 = 0.0001

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3 years ago

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3 years ago

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Nadusha1986 [10]

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