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vladimir2022 [97]
1 year ago
5

Margo is 8 years older than her brother Dan. The sum of their ages is 56. How old is Dan?

Mathematics
1 answer:
daser333 [38]1 year ago
5 0

Answer:

dan is 24

I had to redo this one

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Consider the given density curve.
Gemiola [76]

Answer:

11 is best answer for it ....,..........

4 0
2 years ago
Two similar circles are shown. The circumference of the larger circle, with radius OB, is 3 times the circumference of the small
zheka24 [161]

Answer:

The circumference of the smaller circle is:

C =  2*pi*x/3

Step-by-step explanation:

We know that for a circle of radius R the circumference is given by:

C = 2*pi*R

where pi = 3.14...

Here we have two circles, A and B, where B is the larger circle and A is the smaller circle.

We know that:

The circumference of B is 3 times the circumference of A.

The radius of circle B is: OB = x

The radius of circle A is: OA

We want to find an expression of OA.

The circumference of circle B will be:

C(B) = 2*pi*OB = 2*pi*x

The circumference of circle A will be:

C(A) = 2*pi*OA

And we know that the circumference of circle B is 3 times the circumference of circle A, then:

C(B) = 3*C(A)

replacing the equations for the circumferences, we get:

2*pi*x = 3*(2*pi*OA)

dividing both sides by 2*pi, we get:

x = 3*OA

Now we want to solve this for OA, then we need to isolate it,

x/3 = OA

We can conclude that the radius of the smaller circle is equal to x/3.

Then the circumference of circle A is:

C(A) = 2*pi*x/3

5 0
2 years ago
If n(A) = P and n(B)=q then n(AxB) is (a ) p (b ) q ( c ) p+q ( d ) pq<br><br>​
Butoxors [25]

By way of example, suppose <em>A</em> = {1, 2, 3} and <em>B</em> = {<em>a</em>, <em>b</em>, <em>c</em>}. Then the Cartesian product of <em>A</em> and <em>B</em> is

<em>A</em> × <em>B</em> = {{1, <em>a</em>}, {1, <em>b</em>}, {1, <em>c</em>}, {2, <em>a</em>}, {2, <em>b</em>}, {2, <em>c</em>}, {3, <em>a</em>}, {3, <em>b</em>}, {3, <em>c</em>}}

That is, each element in <em>A</em> gets a pairing with each element in <em>B</em>, and for each pairing you have <em>n(A)</em> choices for the first element and <em>n(B)</em> choices for the second element.

So if <em>n(A)</em> = <em>p</em> and <em>n(B)</em> = <em>q</em>, then <em>n(A</em> × <em>B)</em> = <em>pq</em>.

6 0
3 years ago
X+y=3<br> 2x-y=0 <br> substituition method
Veronika [31]

Answer:

(1, 2 )

Step-by-step explanation:

x + y = 3 (subtract x from both sides )

y = 3 - x → (1)

2x - y = 0 → (2)

Substitute y = 3 - x into (2)

2x - (3 - x) = 0

2x - 3 + x = 0

3x - 3 = 0 ( add 3 to both sides )

3x = 3 ( divide both sides by 3 )

x = 1

Substitute x = 1 into (1)

y = 3 - 1 = 2

solution is (1, 2 )

5 0
2 years ago
..................................................................................
Jobisdone [24]

Answer:

7

Step-by-step explanation:

7 0
2 years ago
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