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3 years ago

What exclusions are placed on the variable x for the fraction 4x^2 +1/4x+2

Mathematics

2 answers:

Darya [45]3 years ago

7 0

<span>4x^2 +1/4x+2
</span>= (4x^2 +1) <span>/ [2(2x + 1)] </span>

2x + 1 = 0, x = -1/2

so

x CAN NOT = - 1/2

zmey [24]3 years ago

5 0

Step-by-step explanation:

The given fraction is as follows.

$\frac{4x^{2}+1}{4x+2}$

It is known that rational expressions are undefined when the denomination is equal to zero.

Therefore, putting the denominator equal to zero as follows.

4x + 2 = 0

4x = -2

Solve for x as follows.

x = $\frac{-2}{4}$

therefore, x = $\frac{-1}{2}$

Thus, exclusion placed on the variable x for the fraction $\frac{4x^{2}+1}{4x+2}$ is $\frac{-1}{2}$ .

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So either

$\cos t=0\implies t=\dfrac{(2n+1)\pi}2$

$12\sin^2t-4\sin t-3=0\implies\sin t=\dfrac{1\pm\sqrt{10}}6\implies t=\sin^{-1}\dfrac{1\pm\sqrt{10}}6+2n\pi$

where $n$ is any integer. We get 8 solutions over the given interval with $n=0,1,2$ from the first set of solutions, $n=0,1$ from the set of solutions where $\sin t=\dfrac{1+\sqrt{10}}6$ , and $n=1$ from the set of solutions where $\sin t=\dfrac{1-\sqrt{10}}6$ . They are approximately