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Nostrana [21]
3 years ago
8

What is the area of BCD?

Mathematics
1 answer:
lbvjy [14]3 years ago
4 0

Answer:

36

Step-by-step explanation:

The length is 12, and the height is 6

A = 1/2 * b*h

So area = 1/2 * 72 = 36

If my answer is incorrect, pls correct me!

If you like my answer and explanation, mark me as brainliest!

-Chetan K

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What is the mode of the data set? 1, 1, 2, 1, 3, 2, 2, and 3
slavikrds [6]

maybe: Mean

=

2.22

Median =

2

Mode =

1

and

3

Explanation:

Mean:

¯

x

=

1

+

2

+

1

+

2

+

1

+

3

+

3

+

4

+

3

9

=

20

9

=

2.22

Median: First we put the numbers in order from lowest to highest:

1

,

1

,

1

,

2

,

2

,

3

,

3

,

3

,

4

The median is the number that has the central position.

Median

=

2

Mode: it is the number that appears the most times. In this case, both

1

and

3

appear the same number of times, so they are both modes.

hope this helps!

8 0
3 years ago
Read 2 more answers
Adecco Workplace Insights Survey sampled men and women workers and asked if they expected to get a raise or promotion this year
Mumz [18]

Answer:

Yes

Step-by-step explanation:

Let p1 represent proportion of women and p2 proportion of men. The null and alternative hypothesis will be as follows

Null hypothesis

H_o=p2-p1 ≤0

Alternative hypothesis

H_a=p2-p1>0

Sample proportion of women, p1=74/200=0.37

Sample proportion of men is p2=104/200=0.52

Level of significance is 0.01

Pooled proportion=\frac {104+74}{200+200}=0.445

Test statistic

z=\frac {(0.52-0.37)-0}{0.445(1-0.445)*\sqrt{(1/200+1/200)}}=6.9124

p-value=P(Z≥z)=P(Z≥6.9124)=P(Z≤-6.9124)=0

Since the value of p is less than 0.01, we reject null hypothesis. There’s sufficient evidence that a greater proportion of men is expecting to get a raise

6 0
4 years ago
824 =20+?+4 how do you work this out
Y_Kistochka [10]
The answer is 800
20+4=24 
824-24=800
800+20+4=824
7 0
4 years ago
Read 2 more answers
Slow and steady wins the race. The leather back sea turtle is the fastest known reptile, with a maximum speed of 21.9221.9221, p
Slav-nsk [51]

Answer:

A and B

Step-by-step explanation:

7 0
4 years ago
Find all pairs of real numbers $(x,y)$ such that $x + y = 6$ and $x^2 + y^2 = 28$. if you find more than one pair, then list you
vivado [14]
1. x^2+y^2=28 and x+y=6

2.  x^2+y^2 and x+y remind us of the formula: (x+y)^{2}= x^2+y^2+2xy

substituting we get: 

 6^{2}= 28+2xy

2xy=36-28
xy=8/2=4

3 Let's solve the system of equations i)x+y=6 and ii)xy=4

substitute y=4/x in (i): 

x+ \frac{4}{x} =6

multiply all sides by x:

x^{2} +4=6x

x^{2} -6x+4=0

complete the square:

x^{2} -6x+4=x^{2} -2*3x+9-9+4= (x-3)^{2}-5=0

x-3=\sqrt{5} or x-3=-\sqrt{5} 

x=3+\sqrt{5} or x=3-\sqrt{5}

so from x+y=6, y=6-x

case 1,  x=3+\sqrt{5} gives y=3-\sqrt{5}

case 2, x=3-\sqrt{5} gives y=3+\sqrt{5} 


Answer: 

(3-\sqrt{5}, 3+\sqrt{5}), (3+\sqrt{5},  3-\sqrt{5})
3 0
3 years ago
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