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diamong [38]
3 years ago
6

Find the ratio of p to s.3p = 8s

Mathematics
1 answer:
blagie [28]3 years ago
6 0
3p : 8s
1p : (8/3)s

So for every one 'p' there is (8/3) 's'

Ratio of p to s is 1 : 8/3

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It's 5 degrees outside and the temperature is expected to drop 4 degrees each hour for the next 3 hours. What will the temperatu
klemol [59]

I think it is - 5 I think

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Please differentiate this problem
strojnjashka [21]

Answer:

dy/dx = d/dx sin(x-3/x+2)

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dy/dx = [5cos(x-3/x+2)]/(x + 2)²

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4 years ago
Find the value of this expression if x = 3
sergeinik [125]
The answer would be -18/-7
6 0
3 years ago
Read 2 more answers
Martin earned the following scores on his last five tests.
egoroff_w [7]
<span>98, 78 , 84, 75, 91
</span>

The interquartile range formula is the first <span>quartile </span>subtracted from the third quartile:

<span>IQR = Q3 – Q1.</span>

<span><span>****************************************************
Step 1: Put the numbers in order.
75, 78, 84, 91, 98

</span><span><span>Step 2: </span><span>Find the median</span>.
</span></span>75, 78, 84, 91, 98
<span>
<span><span>Step 3: </span><span>Place parentheses around the numbers above and below the median. </span>
Not necessary statistically, but it makes Q1 and Q3 easier to spot.
</span></span>(75, 78), 84, (91, 98)
<span>
<span><span>Step 4: </span>Find Q1 and Q3
Think of Q1 as a median in the lower half of the data and think of Q3 as a median for the upper half of data.
</span></span>(75, 78), 84, (91, 98)

<span>*(75, 78) ---> (75 + 78) </span>÷ 2 = 76.5
<span>*(91, 98) ---> (91 + 98) </span>÷ 2 = 94.5
<span>
<span><span>Step 5: </span>Subtract Q1 from Q3 to find the interquartile range.
94.5 – 76.5 = 18

IQR = 18</span></span>
7 0
3 years ago
Read 2 more answers
Two dice are rolled. What is the probability that the sum of numbers rolled is either 5 or 12?
Maksim231197 [3]

<u>ANSWER:  </u>

The probability that sum of numbers rolled is either 5 or 12 is \frac{5}{36}

<u>SOLUTION: </u>

Given, Two dice are rolled.  

We have to find what is the probability that the sum of numbers rolled is either 5 or 12

We know that, probability of an event = \frac{\text { favourable outcomes }}{\text { total outcomes }}

Now, total outcomes for two dices = 6 for 1st dice x 6 for 2nd dice = 6 x 6 = 36.

Now, favourable outcomes = sum is 5 + sum is 12

= 4[(1,4), (2,3), (3, 2), (4, 1)] + 1[(6,6)]

= 5 total favourable outcomes.

Now, probability = 5/36

Hence, the probability that sum is either 5 or 12 is 5/36.

5 0
3 years ago
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