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NeX [460]
4 years ago
15

3 + 4n - 8 + 2x use n = 5 and x = 7

Mathematics
1 answer:
Tom [10]4 years ago
4 0
Your answer is -33!

if you plug it in you get the equation
3+4(5)-8(7)
you’re going to use PEMDAS and first distribute the 5 and 7 so you get the equation
3+20-56
23-56
-33
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2/7 as a percent to the nearest whole number
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3 years ago
Select the correct answer.
Georgia [21]

Answer:

C. transfer $50 per month into a savings account

Step-by-step explanation:

A measurable goal is one measured in a manner that tangible evidence can be presented to show how it was achieved.For example, You can prepare for a Math test on Friday by studying Math every evening and then meeting with your Tutor on Wednesday.

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Eorge sells baseball cards online. He estimates he can make $4.75 per card. If George has 83 cards, using front-end estimation,
qwelly [4]

Answer:

b

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5 0
3 years ago
What is the sum of the finite arithmetic series?
Oksanka [162]
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4 0
3 years ago
Read 2 more answers
BoxedNGone truck rentals calculates that its price function is p(x) = 200 − 2x, where p is the price (in dollars) at which exact
charle [14.2K]

Answer:

At Maximum point;

x(max) = 50

p(max) = $100

Maximum revenue = $5,000

Step-by-step explanation:

The price function is;

p(x) = 200 − 2x

where

p is the price (in dollars) at which exactly x trucks will be rented per day.

The revenue function R(x) can be written as;

R(x) = p(x) × x

Substituting p(x) equation;

R(x) = (200-2x)x

R(x) = 200x-2x^2 ........1

To maximize R(x), at maximum point dR/dx = 0

differentiating equation 1;

dR/dx = 200 - 4x = 0

4x = 200

x = 200/4

x = 50

Substituting x = 50 into p(x)

p(50) = 200 - 2(50) = $100

p = $100

Maximum revenue is;

R = p × x = $100×50

R = $5,000

3 0
3 years ago
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