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aleksklad [387]
3 years ago
8

Circle

Mathematics
1 answer:
Doss [256]3 years ago
8 0
Siras !  Don't try to picture this all in your head !
You'll wear out your brain.
You MUST sketch it on a piece of paper.
Draw an x-axis and a y-axis, then draw the two circles.

I'm drawing myself a picture right now, and I'm
supposed to be some kind of a genius.

a).  In order to move Circle-Q so that both centers are
at the same point, you need to move the center of Q
4 units down and 2 units to the right.
      When you do that, you'll have the little circle inside the
big circle, with their centers both at the same place.

b).  The radius of Q is 2.
       The radius of P is 20.
       What do you have to multiply 2 by, in order to get 20 ?
       THAT's the scale factor to dilate Q so that it has the same
radius as P.
       When you do that, suddenly it'll look like you only have one circle
on the paper ... they'll both have the same radius and their centers are
at the same place, so you can't tell them apart.

c).  All circles are similar !

I went online (you could easily go there too).  I searched the question
"Are circles similar ?" and a lot of interesting stuff came up.  (you could
do that too).  I saw a lot of ways to prove that all circles are similar. 
The best one says:

       Two figures are "similar" if you can make one of them
       exactly fit on top of the other one (make them congruent)
       with translations and dilations.

You just did that with P and Q !

-- Translation is moving them around.
   You moved Q and put the centers of both circles at the same place.

-- Dilation is blowing it up or blowing it down, so its size changes
but its shape doesn't change.
   You blew Q up so that it had the same radius as P.
   Then the two circles exactly fit over/under each other.

So the two circles are similar. 
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In circle A below, chord BC and diameter DAE intersect at F. If arc CD = 46° and arc BE = 78°, what is m_BFE? D B А​
wel

Given:

Consider the below figure attached with this question.

In circle A below, chord BC and diameter DAE intersect at F.

The arc CD = 46° and arc BE = 78°.

To find:

The measure of angle BFE.

Solution:

According to intersecting chords theorem, if two chords intersect inside the circle then the angle on the intersection is the average of intercepted arcs.

Using intersecting chords theorem, we get

m\angle BFE=\dfrac{1}{2}(m(arcCD)+m(arcBE))

m\angle BFE=\dfrac{1}{2}(46^\circ+78^\circ)

m\angle BFE=\dfrac{1}{2}(124^\circ)

m\angle BFE=62^\circ

Therefore, the measure of angle BFE is 62°.

6 0
3 years ago
Michael is preparing to plant a garden with a rectangular bed in the center and equal square beds on either side. The entire len
Marizza181 [45]

Answer:

what

Step-by-step explanation:

8 0
3 years ago
The distance between the cities Atlanta and Indianapolis is 540 miles. A motorcycle's speed is 48 mph. For a car it takes 2.25 h
WITCHER [35]

Answer:

It will take them 5 hours to meet if they start moving towards eachother simultaneusly.

Step-by-step explanation:

Distance, s = 540 miles

Motocycle's speed, v = 48 mph

Time for motorcycle to cover 48 miles, t = \frac{Distance}{Speed}

=  \frac{540}{48} = 11.25 h

For a car it takes 2.25 hours less than 11.25 for motorcycle:

Time for car than becomes: 11.25 - 2.25  = 9 h

Speed for car would be v(c) = \frac{Distance}{Time}

= \frac{540}{9} = 60 mph

<em>For finding when they will meet, we will need relative speed: </em>

Since they are moving towards each other the relative speed is the sum of speed of car and the speed of motorcycle

Relative Speed = 48 + 60 = 108 mph

Distance = 540 miles

Time =  \frac{Distance}{Speed}

        =  \frac{540}{108}

       = 5 hours





6 0
3 years ago
A beach pail is ten inches tall and six inches in diameter. Estimate the amount of water it would hold
Damm [24]
Now, if the diameter is 6 inches, then that means the radius is half that, or 3.

check the picture below.

7 0
3 years ago
Select whether each system of equations has no solution, one solution, or infinitely many solutions.
erik [133]

Answer:

one solution, no solution, infinitely many solutions

Step-by-step explanation:

I rearranged the first equation into x=6-2y

plug that into the second equation

2(6-2y)-3y=26

12-4y-3y=26

12-7y=26

-7y=14

y=-2

Then you plug that into one of the equations

x+2(-2)=6

x-4=6

x=10

The solution to the first system is (10,-2)

the second system already has one equation as something equal to a single variable so you just plug that into the other one

4x-2(2x-4)=-6

4x -4x +8 =-6

8=-6

this is a false statement so the system of equation has no solution

Lastly I rearranged the first equation into y=2x-4 and then plug that in

6x-3(2x-4)=12

6x-6x+12=12

12=12

this statement is true so the system of equations has infinite solutions

5 0
3 years ago
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