Ask question

Ask question

All categories

3 years ago

7

How do you solve this problem (2x+8)2=64

2 answers:

kupik [55]3 years ago

8 0

Answer:

56/4

Step-by-step explanation:

2 is after the () so no need

-8 each side

2x×2

÷2 each side

asambeis [7]3 years ago

7 0

Answer:

12

Step-by-step explanation:

If (2x+8)2 = 64, then I would solve it by making sure the numbers in the parentheses equal 32. This is because it would get multiplied by 2 after you find the answer and 32 x 2 is 64. So what times 2 is 24? 12. 12 x 2 is 24, plus 8 is 32, and multiply 32 by 2 and you get 64 :) I'm not the best at explaining btw ;-;

You might be interested in

If a stack of $10 bills is worth $90 billion what is the height of the stack in kilometers? Assume each bill is 0.2 milimeters t

Shtirlitz [24]

If I am not wrong you would multiply 90 times .2 to get that answer... If so the answer should be 450 kilometers

5 0

3 years ago

Need help on question please!!

Zepler [3.9K]

you'd use the pythagorean theorem.

a^2+b^2=c^2

a is the first leg, b is the second leg, and c is the third leg.

10^2+13^2=c^2

100+169=c^2

269=c^2

take the square root of both sides

16.4=c

16.4cm is your answer!

3 0

4 years ago

Read 2 more answers

What is the answer?<br> 12 x 4 1/2 =?

TiliK225 [7]

Answer:

54

Step-by-step explanation:

What I would do is multiply 12x4 first to get 48, then after I'd multiply 12x1/2 to get 6 then I'd add them together to get 54.

5 0

3 years ago

Classify ABC by its sides. Then determine whether it is a right triangle.

m_a_m_a [10]

Answer:

∴Given Δ ABC is not a right-angle triangle

a= AB = √45 = 3√5

b = BC = 12

c = AC = √45 = 3√5

Step-by-step explanation:

Given vertices are A(3,3) and B(6,9)

$AB = \sqrt{x_{2}-x_{1} )^{2} +(y_{2}-y_{1} )^{2} }$

AB = $\sqrt{(9-3)^{2}+(6-3)^{2} } = \sqrt{6^{2}+3^{2} } =\sqrt{45}$

Given vertices are B(6,9) and C( 6,-3)

$B C = \sqrt{x_{2}-x_{1} )^{2} +(y_{2}-y_{1} )^{2} }$

= $\sqrt{(-3-9)^{2}+(6-6)^{2} } =\sqrt{12^{2} } = 12$

BC = 12

Given vertices are A(3,3) and C( 6,-3)

$AC = \sqrt{(6-3)^{2}+(-3-3)^{2} } = \sqrt{9+36} = \sqrt{45}$

AC² = AB²+BC²

45 = 45+144

45 ≠ 189

∴Given Δ ABC is not a right angle triangle

5 0

3 years ago

∠PMN is congruent to which angle?<br><br> A. ∠CBA<br> B. ∠ABC<br> C. ∠ACB<br> D. ∠CAB

ivolga24 [154]

D. Angle CAB...........

3 0

3 years ago

Read 2 more answers