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solmaris [256]
3 years ago
8

The temperature in the late afternoon was −7.5°C. It dropped 5 degrees by early evening and then dropped another 8.5 degrees by

midnight. What was the temperature at midnight?
Mathematics
1 answer:
Reil [10]3 years ago
4 0

Answer:

-21 is the correct answer

Step-by-step explanation:

-7.5 - 5 - 8.5 = -21

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Which graph does not represent a function ?
baherus [9]

Answer: the the 2nd circular one

Step-by-step explanation: Functions can't just go in a circle, they will repeat the x value

4 0
3 years ago
A girl cut off 2/5 of a ribbon. The piece she cut off was 5 meters long.How
valentinak56 [21]

Answer:

12.5

Step-by-step explanation:

5/2*5=12.5

7 0
3 years ago
Read 2 more answers
after the holiday season, the average number of costumers per day at the game galaxy store decreased from 612 to 450. find the p
andrey2020 [161]
Simple, finding markdown, use these two formulas.

Markdown=Original-New
and
Percent Markdown= Markdown Amount/Original*100

So,

Markdown=612-450
M=162

Markdown%= 162/612*100
M%=0.2647*100
M%=26.5 (rounded)

Thus, there was a 26.5% decrease.
5 0
3 years ago
If cot 0=12/5 find tan 0
jek_recluse [69]

cot 0=12/5 find tan 0

cot = adjacent/opp

tan = opp/adjacent

cot = 12/5

tan = 5/12

8 0
3 years ago
State whether the following coordinates on a Cartesian plane form an acute, obtuse or right triangle: a) (-1, 1), (7,-2) and (1,
LiRa [457]

Answer:

a) Acute triangle

b) Right triangle

Step-by-step explanation:

∵ A triangle having sides a, b and c is called,

Acute : If a² + b² > c² or a² + c² > b² or b² + c² > a²,

Obtuse : if a² + b² < c² or a² + c² < b² or b² + c² < a²

Right : a² + b² = c² or a² + c² = b² or b² + c² = a²,

a) Let A≡(-1, 1), B≡(7,-2) and C≡(1,-5),

By the distance formula,

AB=\sqrt{(7-(-1))^2+(-2-1)^2}=\sqrt{(7+1)^2+(-3)^2}=\sqrt{8^2+3^2}=\sqrt{64+9}=\sqrt{73}\text{ unit}

Similarly,

BC=\sqrt{45}\text{ unit}

CA=\sqrt{40}\text{ unit}

∵ The sum of any two sides is greater than third side,

So, ABC is a triangle,

Now,

AB^2 + BC^2 > CA^2

⇒ ABC is an acute triangle.

b) Let P≡(0,6), Q≡(1,2) and R≡(5,3),

By the distance formula,

PQ = √17 unit,

QR = √17 unit,

RP = √34 unit,

∵ The sum of any two sides of PQR is greater than third side,

⇒ PQR is a triangle ,

Also,

RP^2=PQ^2+QR^2

Hence, PQR is a right triangle.

3 0
4 years ago
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