3 years ago

Describe the motion of a car with an acceleration of –2 m/s2.

Mathematics

1 answer:

AURORKA [14]3 years ago

7 0

I'm not sure exactly about the squared part but that would be going backwards with a rate of -2 m/s.

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$x=0.75 \pm 2.47067i$

Step-by-step explanation:

Quadratic Formula: $x=\frac{-b \pm \sqrt{b^2-4ac} }{2a}$

√-1 is imaginary number i

Step 1: Define

y = -3x² + 4.5x - 20

a = -3

b = 4.5

c = -20

Step 2: Substitute and Evaluate

$x=\frac{-4.5 \pm \sqrt{4.5^2-4(-3)(-20)} }{2(-3)}$

$x=\frac{-4.5 \pm \sqrt{20.25-240} }{-6}$

$x=\frac{-4.5 \pm \sqrt{-219.75} }{-6}$

$x=\frac{-4.5 \pm \sqrt{219.75}(\sqrt{-1} ) }{-6}$

$x=\frac{-4.5 \pm i\sqrt{219.75} }{-6}$

$x=\frac{4.5 \pm i14.824 }{6}$

$x=0.75 \pm 2.47067i$

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