Answer:
Following are the solution to the given question:
Step-by-step explanation:
Please find the complete question in the attached file.

The testing states value is:

therefor the 
Through out the above equation its values Doesn't rejects the H_0 value, and its sample value doesn't support the claim that although the configuration of its dependent variable has been infringed.
I have attached the graph. I did this using desmos.com. Try it out sometime. I hope that helps.
Step-by-step explanation:
A. 2(x+4)=2x+8
=G
B. 3(2x-1)=6x-3
=I
C. 4(x+2)=4x+8
=J
D. 2(x+3)=2x+6
=K
E. 3(4x+1)=12x+3
=H
A - G
B - I
C - J
D - K
E - H
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