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agasfer [191]
3 years ago
6

What is the eighth term of the sequence 2,8,32,128

Mathematics
1 answer:
Hatshy [7]3 years ago
4 0
It's a geometric sequence.

2,8,32,128,... \\ \\
a_1=2 \\
r=\frac{a_2}{a_1}=\frac{8}{2}=4 \\ \\
a_n=a_1 \times r^{n-1} \\
a_8=2 \times 4^{8-1} \\
a_8=2 \times 4^7 \\
a_8=2 \times 16384 \\
a_8=32768

The eighth term of the sequence is 32768.
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In this problem, we have that:

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So 58 is one standard deviation of the mean.

Of those which are above the mean, 68% are within 1 standard deviation of the mean, that is, lesser than 58.

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