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agasfer [191]
3 years ago
6

What is the eighth term of the sequence 2,8,32,128

Mathematics
1 answer:
Hatshy [7]3 years ago
4 0
It's a geometric sequence.

2,8,32,128,... \\ \\
a_1=2 \\
r=\frac{a_2}{a_1}=\frac{8}{2}=4 \\ \\
a_n=a_1 \times r^{n-1} \\
a_8=2 \times 4^{8-1} \\
a_8=2 \times 4^7 \\
a_8=2 \times 16384 \\
a_8=32768

The eighth term of the sequence is 32768.
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Answer:

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(3x^2+21x+33)

--------------------

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Step-by-step explanation:

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I hope my answer has come to your help. Thank you for posting your question here in Brainly.
</span>
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