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mixer [17]
1 year ago
12

I need a simple but deep explanation on how to solve this

Mathematics
1 answer:
never [62]1 year ago
3 0

Let x be the missing side. Since we have a right triangle, we can apply Pythagorean theorem:

x^2+8^2=10^2

Remember that the hypotenuse (10 in our case) is always in front of the right angle. Then, from the last result, we have

x^2+64=100

By subtracting 64 to both sides, we get

x^2=36

then x is given by

\begin{gathered} x=\sqrt[]{36} \\ x=6 \end{gathered}

Therefore, the answer is: 6

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Let x be the first of the four consecutive numbers.

Then x+1 is the second,

and x+2 is the third,

and x+3 is the fourth.

If their sum is 810, then

   x + x+1 + x+2 + x+3 = 810

If you solve that equation for x, you'll have the answer to your question.

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Water has a density of 1.0 g/cm3 a plastic box has a volume of 78 cm and weighs 80 grams will the box sink or float on water
jek_recluse [69]

<u>What we'll do:</u>

A method to find whether an object will float or sink in a liquid is to find it's specific gravity with respect to the liquid, The Specific Gravity tells us the percentage of object's mass which will be submerged in water

<u>Finding the Specific Gravity:</u>

<u>Density of Box:</u>

Density = Mass / Volume

Density = 80 grams / 78 cm³

Density = 1.02 grams/cm³

<u>Specific Gravity of Box with respect to water:</u>

Specific Gravity = Density of Box / Density of Water

we know that density of water is 1 gm/cm³, plugging the values

Specific Gravity = 1.02 / 1

Specific Gravity = 1.02

Hence, 102% of the object will be under water

Q. but I've only heard about 100% of something, how can something be more than 100%?

A. The answer is that the extra 2% over the 100% is providing to the object being even deeper underwater

3 0
3 years ago
A bedroom is in the shape of a rectangle. The length of the bedroom is represented by 3x^2 and the width is represented by 7x+14
pentagon [3]

The area of the room that is not covered by the rug is: 21x^3+26x^2-24x+9

Step-by-step explanation:

Let L be the length of the room

and

W be the width of the room

Then

L = 3x^2

W = 7x+14

Area of the bedroom:

A_r = L*W\\=3x^2(7x+14)\\=21x^3+42x^2

Area of Rug:

Let S be the side of rug

S = 4x+3

A_{rug} =S^2\\=(4x+3)^2\\=(4x)^2+2(4x)(3)+(3)^2\\=16x^2+24x+9

The area of the room that is not covered by the rug will be obtained by subtracting the area of the rug from the area of the room.

So,

Area\ of\ room\ not\ covered\ by\ rug =A_r - A_{rug}\\= 21x^3+42x^2-(16x^2+24x+9)\\=21x^3+42x^2-16x^2-24x-9\\=21x^3+26x^2-24x+9

Hence,

The area of the room that is not covered by the rug is: 21x^3+26x^2-24x+9

Keywords: Rectangle, square

Learn more about area at:

  • brainly.com/question/10703930
  • brainly.com/question/10772025

#LearnwithBrainly

6 0
3 years ago
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