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mixer [17]
1 year ago
12

I need a simple but deep explanation on how to solve this

Mathematics
1 answer:
never [62]1 year ago
3 0

Let x be the missing side. Since we have a right triangle, we can apply Pythagorean theorem:

x^2+8^2=10^2

Remember that the hypotenuse (10 in our case) is always in front of the right angle. Then, from the last result, we have

x^2+64=100

By subtracting 64 to both sides, we get

x^2=36

then x is given by

\begin{gathered} x=\sqrt[]{36} \\ x=6 \end{gathered}

Therefore, the answer is: 6

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Coach Smith went to the sporting goods store to get ready for tennis season. He bought 25 containers of tennis balls and 12 pack
sesenic [268]

Answer:

C

Step-by-step explanation:

143.75+ tax(7.1875)= 150.9375 <-- Tennis Ball Containers

30+ tax(1.5)= 31.5 <-- Packs of Grip Tape

150.9375+31.5= 182.4375

This can be rounded up to 182.44 (which is your final answer)

5 0
3 years ago
Solve the equation identify extraneous solutions
PIT_PIT [208]

Answer:

Step-by-step explanation:

The goal to solving any equation is to have x = {something}.  That means we need to get the x out from underneath that radical.  It's a square root, so we can "undo" it by squaring.  Square both sides because this is an equation.  Squaring both sides gives you

x^2=-3x+40

Get everything on one side of the equals sign and set the quadratic equal to 0:

x^2+3x-40=0

Throw this into the quadratic formula to get that the solutions are x = 5 and -8.  We need to see if only one works, both work, or neither work in the original equation.

Does 5=\sqrt{-3(5)+40}?

5=\sqrt{-15+40} and

5=\sqrt{25}

and 5 = 5.  So 5 works.  Let's try -8 now:

-8=\sqrt{-3(-8)+40} and

-8=\sqrt{24+40} so

-8=\sqrt{64}

-8 = 8?  No it doesn't.  So only 5 works. Your choice is the third one down.

6 0
3 years ago
Need help asap<br> correct answers
Gelneren [198K]

Answer:

line 3

Step-by-step explanation:

3 0
3 years ago
Three fourths of a number p less than two is five sixths of another number r plus five solve for r
maw [93]
r = -3/4p - 18/5 
(or you could put 3.6 or 3 3/5 instead of 18/5)

2 - 3/4p = 5/6r + 5 
-5                     -5
-3 - 3/4p = 5/6r
 /(5/6)       /(5/6) 
-18/5 - 3/4p = r 
-3/4p - 18/5 = r 

5 0
3 years ago
One warehouse had 185 tons of coal, another one had 237 tons. The first warehouse delivered 15 tons of coal to its clients daily
sdas [7]

Given

 One warehouse had 185 tons of coal, another one had 237 tons

The first warehouse delivered 15 tons of coal to its clients daily, the second one delivered 18 tons of coal to its clients daily.

Find out in how many days will the second warehouse have 1.5 times more coal than the first one.

To proof

Let us assume that the number of days of delivered the coal = x

Take two cases

First case

As given in the question

One warehouse had  coal = 185 tons

The first warehouse delivered 15 tons of coal to its clients daily

(As first warehouse delivered 15 tons of coal to its clients daily than the total amount of coal decrease daily as days increase)

Than the equation becomes for first warehouse

= ( 185 - 15x)

( this equation represent the amount of coal left after x days)

Second case

second warehouse had  coal = 237 tons

the second one delivered 18 tons of coal to its clients daily.

(As first warehouse delivered 18 tons of coal to its clients daily than the total amount of coal decrease daily as days increase)

Than the equation becomes for the second warehouse

= ( 237 - 18x)

( this equation represent the amount of coal left after x days)

As given in the question

the second warehouse have 1.5 times more coal than the first one

Thus

( 237 -18x ) = 1.5× ( 185 - 15x)

237 - 18x = 277.5 - 22.5x

22.5x - 18x = 277.5 - 237

4.5x = 40.5

x = 9

Therefore  the second warehouse have 1.5 times more coal than the first one in 9 days.

Hence proved

7 0
3 years ago
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