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3 years ago

15

ANSWER ASAP QUESTION IS ON IMAGE PLEASE WILL MARK BRAINIEST!!!!!!

1 answer:

Marianna [84]3 years ago

3 0

XY is the rightmost side of the rectangle. Since you have the image already graphed, you can just <u>count</u> how many units there are from X to Y.

If you are starting at point X and you walk to point Y, how many "lines" do you cross to get there?
Answer: 4 units

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Write an<br> equation of a line that passes through each pair of points.<br> (-2,6) (0,0)

arlik [135]

Answer: y= -3x

(there is no y-intercept in the points you listed so if you can find one on a picture of your question, do so. but since i do not see a given y-intercept, i assume it is 0)

To find the slope, use the two points given.

1st: subtract the y-values. 0-6= -6.

2nd: subtract the x-values. 0-(-2)= 2

3rd: you have -6/2.

4th: simplify to get a slope of -3.

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3 years ago

Cynthia clones 50 frogs in a year.

Dima020 [189]

There are 52 weeks in a year. 1 frog per week: 52 * 1 = 52

So, cloning about 1 frog per week would be reasonable.

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3 years ago

Carter draws one side of equilateral △PQR on the coordinate plane at points P(-3,2) and Q(5,2). Which ordered pair is a possible

Law Incorporation [45]

Step-by-step explanation:

Hey, there!!!

Let me simply explain you about it.

We generally use the distance formula to get the points.

let the point R be (x,y)

As it an equilateral triangle it must have equal distance.

now,

let's find the distance of PQ,

we have, distance formulae is;

$pq = \sqrt{( {x2 - x1)}^{2} + ( {y2 - y1)}^{2} }$

$or \: \sqrt{( {5 + 3)}^{2} + ( {2 - 2)}^{2} }$

By simplifying it we get,

$8$

Now,

again finding the distance between PR,

$pr = \sqrt{( {x2 - x1}^{2} + ( {y2 - y1)}^{2} }$

or,

$\sqrt{( {x + 3)}^{2} + ( {y - 2)}^{2} }$

By simplifying it we get,

$= \sqrt{ {x}^{2} + {y}^{2} + 6x - 4y + 13 }$

now, finding the distance of QR,

$qr = \sqrt{( {x - 5)}^{2} + ( {y - 2)}^{2} }$

or, by simplification we get,

$\sqrt{ {x}^{2} + {y}^{2} - 10x - 4y + 29 }$

now, equating PR and QR,

$\sqrt{ {x}^{2} + {y}^{2} + 6x - 4y + 13} = \sqrt{ {x}^{2} + {y}^{2} - 10x - 4y + 29 }$

we cancelled the root ,

${x}^{2} + {y}^{2} + 6x - 4y + 13 = {x}^{2} + {y}^{2} -10x - 4y + 29$

or, cancelling all like terms, we get,

6x+13= -10x+29

16x=16

x=16/16

Therefore, x= 1.

now,

equating, PR and PQ,

$\sqrt{ {x}^{2} + {y}^{2} + 6x - 4y + 13 } = 8}$

cancel the roots,

${x}^{2} + {y}^{2} + 6x - 4y + 13 = 8$

now,

(1)^2+ y^2+6×1-4y+13=8

or, 1+y^2+6-4y+13=8

y^2-4y+13+6+1=8

or, y(y-4)+20=8

or, y(y-4)= -12

either, or,

y= -12 y=8

Therefore, y= (8,-12)

by rounding off both values, we get,

x= 1

y=(8,-12)

So, i think it's (1,8) is your answer..

<em>Hope it helps</em><em>.</em><em>.</em><em>.</em>

3 0

3 years ago

U can help me with this

zvonat [6]

$16.50 since you want to multiply the budget per person by how many people their are

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3 years ago

What goes in water black and comes red?

NNADVOKAT [17]

Answer:lobster

Step-by-step explanation:

6 0

3 years ago

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