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Ksivusya [100]
3 years ago
15

ANSWER ASAP QUESTION IS ON IMAGE PLEASE WILL MARK BRAINIEST!!!!!!

Mathematics
1 answer:
Marianna [84]3 years ago
3 0
XY is the rightmost side of the rectangle.  Since you have the image already graphed, you can just <u>count</u> how many units there are from X to Y.

If you are starting at point X and you walk to point Y, how many "lines" do you cross to get there?
Answer: 4 units
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How to completely factor t^2+4tv+4v^2
Anna71 [15]
<span> t^2+4tv+4v^2
= (t + 2v)(t + 2v)
= (t + 2v)^2</span>
8 0
3 years ago
A test has multiple choice questions with 3 choices for each answer; only one answer is correct for each question. Suppose a stu
posledela

Answer:

a

Step-by-step explanation:

4 0
3 years ago
How do I divide numbers by using long division. <br>​
Vsevolod [243]

The only rule to follow is

Divide dividend by divisor and the mention the quotient and things left after remains in place of remainder

Here is a sample

\sf\Large\qquad\quad16\\ \begin{array}{cc} \cline{2 - 2}\sf 20 )&\sf \ 327\\&\sf - 20 \downarrow\\ \cline{2-2}& \sf \ \ \ \ 127\\ &\sf \ - 120 \\ \cline{2-2} & \sf \ \007 \\ \cline{2-2} \end{array}\\\\\\ \sf Divisor \rightarrow 20 \\ \\ \sf Quotient \rightarrow 16\\\\ \sf Remainder \rightarrow 7

3 0
2 years ago
Prove the following statement.
gayaneshka [121]

Answer:

You can prove this statement as follows:

Step-by-step explanation:

An odd integer is a number of the form 2k+1 where k\in \mathbb{Z}. Consider the following cases.

Case 1. If k is even we have: (2k+1)^{2}=(2(2s)+1)^{2}=(4s+1)^{2}=16s^2+8s+1=8(2s^2+s)+1.

If we denote by m=2s^2+2 we have that (2k+1)^{2}=8m+1.

Case 2. if k is odd we have: (2k+1)^{2}=(2(2s+1)+1)^{2}=(4s+3)^{2}=16s^2+24s+9=16s^{2}+24s+8+1=8(2s^{2}+3s+1)+1.

If we denote by m=2s^{2}+24s+1 we have that (2k+1)^{2}=8m+1

This result says that the remainder when we divide the square of any odd integer by 8 is 1.

6 0
3 years ago
Please response ASAP!<br><br> 2+3=<br> 9+2=<br> 0+1=<br> 7+4=
Stolb23 [73]

2+3=5

9+2=11

0+1=1

7+4=11

3 0
3 years ago
Read 2 more answers
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