Absolute value so the answer can be positive or negative
R+3>7
-3>-3
R>4
Or
R-3>7
+3>+3
R>10
Answer
410



so hmm if you notice, your f(x) there, looks just like g(x), but is "shifted horizontally" by about 9 units to the right
that simply means, based on that template above, that C/B = -9, and we can simply make B = 1 and C = -9, and we get C/B = -9/1 which is -9
thus
The standard form:
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The point-slope form:

m - slope
The formula of a slope:

We have the points (6, 1) and (5, 4). Substitute:

<em>use distributive property</em>
<em>add 1 to both sides</em>
<em>add 3x to both sides</em>

What is the median of the data below?<br><br>
45, 19, 23, 67, 28, 35, 46, 21, 58, 60, 23, 51
VLD [36.1K]
To find the median, you will need to list the data from least to greatest and find the middle number.
19, 21, 23, 23, 28, 35, 45, 46, 51, 58, 60, 67
Cross out a number on both sides until you reach the middle number. In this case, we are left with 2 numbers that are in the middle since there is an even amount of numbers.
When you reach the time where you have two middle numbers, we have to find the average of those two numbers. Our two middle numbers are 35 and 45. Since we have to find the average of those two numbers, we can add them. (35 + 45 = 80). Now, since we have two middle numbers, we have to divide them by 2.

Answer:
the tempayure was at six because it was at 92c and went down to -13c then rose 7c so that means it was at 6 by 6 a.m.