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4 years ago

5

Mr. and Mrs. Lorenzo want to buy a home valued at $213,500. If they have 18% of this amount saved for a down payment, how much h

ave they saved? a. $384.30 b. $3,843.00 c. $38,043.00 d. $38,430.00

1 answer:

romanna [79]4 years ago

5 0

It would be: 213500 * 18/100
213500 * 0.18 = $38430

So, option D is your answer.

Hope this helps!

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The table shows the time Merrida spent driving and the number of miles she drove. She drove the same number of miles each hour.

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Answer:

20

Step-by-step explanation:

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3 years ago

In general, the eigenvalues of an upper triangular matrix are given by the entries on the diagonal. The same is true for a lower

SCORPION-xisa [38]

Answer:

Verified!

Step-by-step explanation:

Upper or lower triangular matrix does not make any difference in finding eigenvalues because equalizing determinant to zero will lead to the same result.

Let's apply it for 2x2 matix:

$A = \left[\begin{array}{ccc}a&0\\b&c\end{array}\right]\\\\\lambda I - A = \left[\begin{array}{ccc}\lambda&0\\0&\lambda\end{array}\right]-\left[\begin{array}{ccc}a&0\\b&c\end{array}\right]\\\\det(\lambda I - A) = det\left[\begin{array}{ccc}\lambda-a&0\\-b&\lambda-c\end{array}\right]=(\lambda-a)(\lambda-c)=0$

So, eigenvalues are entries on the diagonal because zeros in upper side or lower side vanishes the remaining part and only we have $(\lambda-a)(\lambda-c)$ .

So, eigenvalues are $\lambda_1=a,\:\lambda_2=c$

Let's apply it for 3x3 matrix:

$A = \left[\begin{array}{ccc}a&0&0\\b&c&0\\d&e&f\end{array}\right]\\\\\lambda I - A = \left[\begin{array}{ccc}\lambda&0&0\\0&\lambda&0\\0&0&\lambda\end{array}\right]-\left[\begin{array}{ccc}a&0&0\\b&c&0\\d&e&f\end{array}\right]\\\\det(\lambda I - A) = det\left[\begin{array}{ccc}\lambda-a&0&0\\-b&\lambda-c&0\\-d&-e&\lambda-f\end{array}\right]=(\lambda-a)(\lambda-c)(\lambda-f)=0$

So as above, eigenvalues are entries on the diagonal because zeros in upper side or lower side vanishes the remaining part and only we have $(\lambda-a)(\lambda-c)(\lambda-f)$ .

So eigenvalues are $\lambda_1=a,\:\lambda_2=c,\:\lambda_3=f$

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4 years ago

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Illusion [34]

The correct answer for this is A

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4 years ago

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bazaltina [42]

23x2=x
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3 years ago

A matrix with 5 columns and 6 rows added to another matrix with 5 columns and 6

jasenka [17]

Option B - 5 columns and 6 rows is the correct answer

Step-by-step explanation:

Step 1 :

Given,

Number of columns of first matrix = 5

Number of rows of first matrix = 6

Number of columns of second matrix = 5

Number of rows of second matrix = 6

We need to determine number of rows and columns of the resultant matrix.

Step 2 :

When a matrix of dimension m × n is added to another m × n matrix, the resultant matrix is also a m × n matrix.

Hence when a matrix with 5 columns and 6 rows added to another matrix with 5 columns and 6 rows the resultant matrix will also have 5 columns and 6 rows.

Step 3 :

Answer :

Option B - 5 columns and 6 rows is the correct answer

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3 years ago