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rusak2 [61]
3 years ago
5

What the length of the line BX? (please see attachment)

Mathematics
2 answers:
sveticcg [70]3 years ago
3 0
It equals 10 are supposed to divide the whole line by 3 to get the smaller segment then double it to get the larger segment
Nina [5.8K]3 years ago
3 0
The length of BX is 10 cm 
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PLZ QUICK!!
iragen [17]

Answer:

See attached graph

Step-by-step explanation:

The equation is y-3=(x + 6)

Write the equation in a slope intercept form, then graph the equation on a graph tool to see the points that line on the line.

Alternatively , using the coordinates in the answer choices given, input them in the equation of the graph and select the answer choice that has all its coordinates true to the equation.

y-3 = x+6  -----can be written as : y= x+9

Graph  y= x+9 to see the graph and the points that are on the line as attached.

3 0
3 years ago
Read 2 more answers
Ac is tangent to circle o at point c what is the length of ac?
MissTica

Answer:

The Answer is 12

Step-by-step explanation:

Use Pythagorean theorem. AB=8 and BO=5 We still need to find AO

AO=AB+BO

8+5

AO=13

Now solve for AC

AC^2 + OC^2= AO^2

AC^2+5^2=13^2

AC^2+ 25=169

AC^2=144

AC= 12

5 0
3 years ago
Find the quotient. Write your answer as a decimal.<br> 12.42 divided by (-4.8) =
MakcuM [25]

Answer:

Multiply the divisor by a power of 10 to make it a whole number.

Multiply the dividend by the same power of 10. Place the decimal point in the quotient.

Divide the dividend by the whole-number divisor to find the quotient.

7 0
2 years ago
Find the volume of this rectangular pyramid.
LekaFEV [45]

Answer:

25 ft

Step-by-step explanation:

You need to add 9+7+9.

There are two 9s and just one 7. 9+9 is 18 and 18+7 is 25

5 0
3 years ago
Find sin theta if cot theta = -2 and cos theta &lt; 0
Katarina [22]

cot(<em>θ</em>) = cos(<em>θ</em>)/sin(<em>θ</em>)

So if both cot(<em>θ</em>) and cos(<em>θ</em>) are negative, that means sin(<em>θ</em>) must be positive.

Recall that

cot²(<em>θ</em>) + 1 = csc²(<em>θ</em>) = 1/sin²(<em>θ</em>)

so that

sin²(<em>θ</em>) = 1/(cot²(<em>θ</em>) + 1)

sin(<em>θ</em>) = 1 / √(cot²(<em>θ</em>) + 1)

Plug in cot(<em>θ</em>) = -2 and solve for sin(<em>θ</em>) :

sin(<em>θ</em>) = 1 / √((-2)² + 1)

sin(<em>θ</em>) = 1/√(5)

6 0
2 years ago
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