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Stella [2.4K]
3 years ago
15

you put your money into a savings account, and it warns interest find the simple interest paid on your investment of $1675 with

2% interest over ten years
Mathematics
1 answer:
earnstyle [38]3 years ago
8 0

Answer:

<h2>$335</h2>

Step-by-step explanation:

p = 1675 \\ r = 2\% \\ t = 10 \:  \: years

Now let's find the simple interest.

\frac{prt}{100}  \\  =  \frac{1675 \times 2  \times 10}{100}  \\  =  \frac{3350}{10}  \\  =  335

hope this helps

brainliest appreciated

good luck! have a nice day!

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34, 41 the pattern is +7
5 0
3 years ago
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You get a job making $12 per hour. You do a great job and your boss says he is going to give you a 25% raise!!! What is your new
AURORKA [14]

Answer:

15

Step-by-step explanation:

10% of 12 =1.2

1.2*2= 2.4 (20%)

1.2/2= 0.6 (5%)

2.4+0.6= 3

12+3= $15

3 0
3 years ago
Can someone help me and explain how to do it.
skelet666 [1.2K]

Answer:

uhhhhhhh you have to figure out what x is then choose wether it is the other variable a dependent variable, and explanatory variable, or a response variable

Step-by-step explanation:

easy as that

4 0
3 years ago
1. Use the formula S(d)=√9.8d to calculate the estimated speed, in meters per second, of a tsunami if the disturbance occurred a
postnew [5]

Answer: 1. 210 meters per second .

2.  756  kilometers per hour.

Step-by-step explanation:

Given : The formula S(d)=\sqrt{9.8d} to calculate the estimated speed, in meters per second of a tsunami.

1. If the disturbance occurred at an ocean depth of 4,500 meters.

Then put d= 4500 in the above formula , we get

S(d)=\sqrt{9.8\times4500}

S(d)=\sqrt{44100}=\sqrt{21\times21\times10\times10}\\\\=\sqrt{210^2}=210

Hence, if the disturbance occurred at an ocean depth of 4,500 meters , the estimated speed would be 210 meters per second .

Also, A meter per second is equal to 3.6 kilometers per hour.

i.e. 1 meter per second = 3.6 kilometers per hour

Then by unitary method ,

210 meters per second  =3.6\times210 kilometers per hour

=756  kilometers per hour.

3 0
3 years ago
How do I resolve this? <br> Como resuelvo esto?
Nikolay [14]

\bf \textit{area of a circle}\\\\ A=\pi r^2~~ \begin{cases} r=radius\\ -----\\ A=144\pi  \end{cases}\implies 144\pi =\pi r^2\implies \cfrac{144\pi }{\pi }=r^2 \\\\\\ 144=r^2\implies \sqrt{144}=r\implies \boxed{12=r} \\\\\\ \textit{circumference of a circle}\\\\ C=2\pi r\qquad \qquad C=2\pi \boxed{12}\implies C=24\pi

4 0
3 years ago
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