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Leni [432]
3 years ago
13

A new manager of a small convenience store randomly samples 20 purchases from yesterday’s sales. The mean was $45.26 and the sta

ndard deviation was $20.67. We wish to test for evidence that the overall mean purchase amount is at least $40? What is the value of the t-statistic for this test (three decimal places)?
Mathematics
1 answer:
zhannawk [14.2K]3 years ago
6 0

Answer:

The value of the t-statistic for this test is 1.138.

Step-by-step explanation:

We are given that a new manager of a small convenience store randomly samples 20 purchases from yesterday’s sales. The mean was $45.26 and the standard deviation was $20.67.

We wish to test for evidence that the overall mean purchase amount is at least $40

<u />

<u><em>Let </em></u>\mu<u><em> = overall mean purchase amount</em></u>

SO, <u>Null Hypothesis</u>, H_0 : \mu \geq $40   {means that the overall mean purchase amount is at least $40}

<u>Alternate Hypothesis</u>, H_A : \mu < $40   {means that the overall mean purchase amount is less than $40}

The test statistics that will be used here is <u>One-sample t test statistics</u> because we don't know about the population standard deviation;

                           T.S.  = \frac{\bar X -\mu}{{\frac{s}{\sqrt{n} } } }  ~ t_n_-_1

where,  \bar X = sample mean sale = $45.26

              s = sample standard deviation = $20.67

              n = sample of purchases = 20

So, <u><em>test statistics</em></u>  =  \frac{45.26-40}{{\frac{20.67}{\sqrt{20} } } }  ~ t_1_9

                               =  1.138

<em>Hence, the value of the t-statistic for this test is 1.138.</em>

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