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leva [86]
3 years ago
11

Inequality on a graph

Mathematics
1 answer:
Reil [10]3 years ago
8 0

Answer:

the last one

Step-by-step explanation:

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The radius r of the base of a cone is given by the equation r=(3V/piH)
lyudmila [28]

Answer:

<h3>1 in</h3>

Step-by-step explanation:

Given the expression to calculate the radius r of the base of a cone is given by the equation

r=(3V/piH)

v is the volume = 5in^3

H = 4in

pi = 3.14

Substitute

r = 3(5)/3.14(4)

r = 15/12.56

r = 1.19

r = 1in to the nearest inch

5 0
3 years ago
Please help me with this question
asambeis [7]

Answer:

For every book Chloe read Peyton read 5

Step-by-step explanation:

Chloe  : Peyton

11   : 55

Divide each by 11

11/11  : 55/11

1 : 5

For every book Chloe read Peyton read 5

5 0
3 years ago
Solve. Express your answer as a simplified mixed number
Semmy [17]
Stick change flip
5/6 x 10/3 = 50/18 2 14/18 simplify 2 7/9
7 0
3 years ago
Read 2 more answers
The region in the first quadrant bounded by the x-axis, the line x = ln(π), and the curve y = sin(e^x) is rotated about the x-ax
charle [14.2K]
First, it would be good to know that the area bounded by the curve and the x-axis is convergent to begin with.

\displaystyle\int_{-\infty}^{\ln\pi}\sin(e^x)\,\mathrm dx

Let u=e^x, so that \mathrm dx=\dfrac{\mathrm du}u, and the integral is equivalent to

\displaystyle\int_{u=0}^{u=\pi}\frac{\sin u}u\,\mathrm du

The integrand is continuous everywhere except u=0, but that's okay because we have \lim\limits_{u\to0^+}\frac{\sin u}u=1. This means the integral is convergent - great! (Moreover, there's a special function designed to handle this sort of integral, aptly named the "sine integral function".)

Now, to compute the volume. Via the disk method, we have a volume given by the integral

\displaystyle\pi\int_{-\infty}^{\ln\pi}\sin^2(e^x)\,\mathrm dx

By the same substitution as before, we can write this as

\displaystyle\pi\int_0^\pi\frac{\sin^2u}u\,\mathrm du

The half-angle identity for sine allows us to rewrite as

\displaystyle\pi\int_0^\pi\frac{1-\cos2u}{2u}\,\mathrm du

and replacing v=2u, \dfrac{\mathrm dv}2=\mathrm du, we have

\displaystyle\frac\pi2\int_0^{2\pi}\frac{1-\cos v}v\,\mathrm dv

Like the previous, this require a special function in order to express it in a closed form. You would find that its value is

\dfrac\pi2(\gamma-\mbox{Ci}(2\pi)+\ln(2\pi))

where \gamma is the Euler-Mascheroni constant and \mbox{Ci} denotes the cosine integral function.
5 0
4 years ago
(01.04 NC The elevation of oty is 80 feet below sea level: the elevation of city is 18 feet below sea level. The elevation of pa
ser-zykov [4K]

Step-by-step explanation:

how the elevation of city can be seen below the sea level

6 0
3 years ago
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