If there is a gene with four alleles A1, A2, A3, and A4 then six distinct heterozygous genotypes are possible because A1 cross A2, A1 cross A3, A1 cross A4, A2 cross A3, A2 cross A4, A3 cross A4 will be formed and other will be similar so therefore only six genotypes are possible for distinct heterozygous traits.
This can be solved either by using a Punnet Square or you can use the formula (n(n+1))/2, where n is the number of alleles. However, using either method will give you the number of possible genotypes regardless if it's homozygous or heterozygous. If we use the second formula, that will give you 10 possible genotypes. Since you only want to know the number of heterozygous genotypes, you should subtract the number of possible homozygous genotypes. In this case, there are four. That is (A1,A1), (A2,A2), (A3,A3), and (A4,A4). Knowing this, you'd be able to figure out that there are six heterozygous genotypes.
Adipose tissue consisting mainly of fat cells (adipose cells, or adipocytes), specialized to synthesize and contain large globules of fat. It is found mainly under the skin but also between the muscles, in the intestines, around the heart, and e It is also found in the bone marrow
-Enzyme polynucleotide phosphorylase does not need a template; and, it could use as little as 1 NDP or as many as 4 NDPs as substrate. In fact, the sequence of the product RNA depended entirely on the number and concentration of substrate NDPs.
-The enzyme was subsequently determined that the enzyme’s function is to degrade RNA, not synthesize it; under test-tube conditions, however, it runs its natural reaction in reverse.