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3 years ago

What is the slope of the line? y +3 = -4(x+7)

Mathematics

2 answers:

Svetach [21]3 years ago

8 0

Answer:

-4

Step-by-step explanation:

Compare this to the form ...

y -y1 = m(x -x1)

which is the point-slope form of the equation for a line. Matching the parts of the equation, you see that ...

y1 = -3
m = -4
x1 = -7

m represents the slope of the line. The slope is -4.

GrogVix [38]3 years ago

7 0

Answer:

-4

Step-by-step explanation:

We need to go over point-slope form:

y - y1 = m(x - x1)

In this equation m represents the slope

So, let's convert:

y +3 = -4(x+7)

m being -4, so the slope of the line is -4.

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Simplify y 2 + 11y - 6y + y 2.<br><br> A y4 + 5<br> B y4 + 5y<br> C 2y 2 + 5<br> D 2y 2 + 5y

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D) 2y 2 + 5y
It should be D

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3 years ago

Read 2 more answers

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Law Incorporation [45]

Answer:

Step-by-step explanation:

To solve this problem, we will use the following two theorems/definitions:

- Given a vector field F of the form (P(x,y,z),Q(x,y,z),W(x,y,z)) then the divergence of F denoted by $\nabla \cdot F = \frac{\partial P}{\partial x}+\frac{\partial Q}{\partial y}}+\frac{\partial W}{\partial z}$

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$\int_{S} F\cdot \vec{n} dS = \int_{V} \nabla \cdot F dV$

where n is the normal vector pointing outward of the surface and V is the volume bounded by the surface S.

Let us, in our case, calculate the divergence of the given field. We have that

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Hence, by the Gauss theorem we have that

$\int_{S} F\cdot \vec{n} dS = \int_{V} 8 dV = 8\cdot\text{Volume of V}$

So, we must calculate the volume V bounded by the cube S.

We know that the vertices are located on the given points. We must determine the lenght of the side of the cube. To do so, we will take two vertices that are on the some side and whose coordinates differ in only one coordinate. Then, we will calculate the distance between the vertices and that is the lenght of the side.

Take the vertices (1,1,1) and (1,1-1). The distance between them is given by

$\sqrt[]{(1-1)^2+(1-1)^2+(1-(-1)^2} = \sqrt[]{4} = 2$ .

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$\int_{S} F\cdot \vec{n} dS =8\cdot 8 = 64$

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3 years ago

ABCD is a rectangle. The measure of angle BCE is 4x-23 and the angle measure of angle DCE is 5+5x. Find the measure of angle BEC

Temka [501]

<h2>Explanation:</h2><h2></h2>

The diagram for this problem is shown below. Point E is the intersection of the two diagonals and we know that:

$\angle BCE=\beta \\ \\ \angle DCE=\theta$

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$\beta +\alpha=90 \\ \\ (4x-23)+(5+5x)=90 \\ \\ \\ Isolating \ x: \\ \\ (4x+5x)+(5-23)=90 \\ \\ 9x-18=90 \\ \\ 9x=108 \\ \\ x=\frac{108}{9}=12$

So:

$\beta=4x-23=4(12)-23=25^{\circ}$

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We know that triangle ΔCEB is an isosceles triangle because the diagonals of any rectangle measure the same. So

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Bogdan [553]

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Step-by-step explanation:

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