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MArishka [77]
3 years ago
14

Can someone please help me with this!?!?!

Mathematics
1 answer:
lys-0071 [83]3 years ago
4 0
They are congruent because of the angles, which means the congruency reason should be SAS.
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Why is it necessary to apply inverse operations on both sides of the equals l sign when solving an equations
liraira [26]
Take this example (cause it's easy to explain)

10+5x=15x

To solve it we have to minus five on both side. We have to do this because we need to isolate the variable (in this case x) on the one side so we can divide and solve.

You would -5x (inverse from positive 5) from both sides on this because whatever you do to one side you have to do to the others to make it equal. In this case the answer would be x=1 (again cause it's easy lol.)

I hope this helps you!
8 0
3 years ago
Which expression is equivalent
Artist 52 [7]
I would say c
Ccccccccccccccccccccccc
8 0
2 years ago
Determine whether the equation below has a one solutions, no solutions, or an
lesantik [10]

The equation below does not have one solution, or no solutions, but instead it has an infinite number of solutions

<h3>How to determine whether the equation below has a one solutions, no solutions, or an infinite number of solutions?</h3>

The equation is given as:

x + 2 = 2 + x

Collect the like terms

x - x =2 - 2

Evaluate the like terms

0 = 0

An equation that has a solution of 0 = 0 has an infinite number of solutions

Possible values of x are x = 8 and x = -8

Hence, the equation below does not have one solution, or no solutions, but instead it has an infinite number of solutions

Read more about number of solutions at

brainly.com/question/24644930

#SPJ1

4 0
2 years ago
1 of 9
alexandr1967 [171]

Answer: 40 800‬

idk if it is the answer but i just times it

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Three machines A, B, and C produce 55%, 25% and 20% respectively. The percentages of defective output are 3.5%, 4.5% and 5.5%. I
pishuonlain [190]

We are given the following information concerning the three production machines;

\begin{gathered} Of\text{ the total production;} \\ A=55\text{ \%}=0.55 \\ B=25\text{ \%}=0.25 \\ C=20\text{ \%}=0.20 \end{gathered}

Also, we are given the percentage of defective output as follows;

\begin{gathered} A=3.5\text{ \%}=0.035 \\ B=4.5\text{ \%}=0.045 \\ C=5.5\text{ \%}=0.055 \end{gathered}

Therefore, if an item is selected randomly, the probability that the item is defective would be;

\begin{gathered} P\lbrack defective\rbrack=(0.55\times0.035)+(0.25\times0.045)+(0.20\times0.055) \\ P\lbrack\text{defective\rbrack}=0.01925+0.01125+0.011 \\ P\lbrack\text{defective\rbrack}=0.0415 \end{gathered}

ANSWER:

The probability that the item is defective would be 0.0415

6 0
1 year ago
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