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Marianna [84]
3 years ago
15

What is the purpose of multiplying by the conjugate of a complex denominator when finding the quotient of complex numbers?

Mathematics
1 answer:
Vinil7 [7]3 years ago
3 0

Answer: To have a real number in the denominator

Step-by-step explanation:

Ok, a quotient between two complex numbers can be written as:

\frac{A  +  Bi}{C+Di}

Now, when we do these types of divisions, we multiply and divide by the same number (so in essence we are multiplying by one) that is the conjugate of the denominator.

Remember that for a complex number:

Z = A + Bi

the conjugate is = A - Bi.

Then, wen we multiply the denominator by it's conjugate, we have:

(C + Di)(C - Di) = C^2 + D*C*i - D*C*i + (D*i)*(-D*i) = C^2 + D^2

So now we have a real number in the denominator (the imaginary part of this number is equal to zero)

So the answer to the question is:

"To have a real number in the denominator"

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Answer:

(6,-4)

Step-by-step explanation:

P(-2,2)

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2 - 6 = -4

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3 years ago
Richard is $15 overdrawn on his checking account. He writes a check for $7. What is the balance in his checking account now?​
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Since he’s already at -15, if he writes a check for 7 then he’s subtracting more from his account.
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5 0
3 years ago
Help asap!!!!!!!!!! Thank u
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Answer:

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Step-by-step explanation:

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3 years ago
Which choice names a radius of circle F?
ella [17]

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3 years ago
Simplify
OlgaM077 [116]

Answer:

see below

Step-by-step explanation:

\frac{x-1}{x^2-3x+2}+ \frac{x-2}{x^2-5x+6} +\frac{x-5}{x^2-8x+15}

we need to simplify that

x^2-3x+2=(x-1)(x-2)\\\\x^2-5x+6=(x-2)(x-3)\\\\x^2-8x+15=(x-3)(x-5)

so we can continue

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and we can put all together

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3 years ago
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