All the numbers from 1 to 100 that have 13 as a factor

Circle A has an area of 452.16ft2. With a radius of 12 ft. If circle B has a radius of 17 ft, what is it’s area?

ehidna [41]

Answer: 907.92 ft²

Step-by-step explanation:

1. To solve this problem you must apply the formula for calculate the area of a circle, which is shown below:

$A=r^{2}\pi$

Where r is the radius of the circle.

2. You know the radius of the circle B, therefore, when you susbtitute it into the formula, you obtain that the area of the circle B is:

$A_B=(17ft)^{2}\pi=907.92ft^{2}$

7 0

3 years ago

Read 2 more answers

6000 increased by 145%

Lisa [10]

Your question would be clearer if written as "What is 145% of 6000?"

1.45(6000) = 8700

8 0

3 years ago

Plz help and thanks so much for it

kirza4 [7]

B+c+(c-b)+(b-c). That is your expression. b 11 c 16

First, let's convert the variables to real numbers: 11+16+(16-11)+(11-16)
Now, let's solve that equation. 11+16+5+(-5)
5+(-5) cancels out, so all we have left is: 27
That is your perimeter.

7 0

3 years ago

Which is an equation for the circle with a center at (-2, 3) and a radius of 3?

kkurt [141]

Answer:

(x+2)^2 +(y-3)^2 = 9

Step-by-step explanation:

(x-h)^2 +(y-k)^2 = r^2

Where (h, k) is the center of the circle

And r is the radius of the circle.

Hope this helps.

6 0

3 years ago

At the start of the year, 15 chameleons were introduced into a zoo. The population of chameleons is expected to grow at a rate o

bearhunter [10]

Answer:

option-B

Step-by-step explanation:

We are given

At the start of the year, 15 chameleons were introduced into a zoo

so, $P_0=15$

The population of chameleons is expected to grow at a rate of 41.42% every year

so, r=0.4142

and x represents the number of years since the chameleons were introduced into the zoo

now, we can set equation to find total population

and we get

$P(x)=P_0(1+r)^x$

now, we can plug values

$P(x)=15(1+0.4142)^x$

$P(x)=15(1.4142)^x$

Average rate of change between 2 years and 4 years:

we can use formula

$A_1=\frac{P(4)-P(2)}{4-2}$

now, we can plug values

$A_1=\frac{15(1.4142)^{4}-15(1.4142)^{2}}{4-2}$

$A_1=14.99914$

Average rate of change between 4 years and 6 years:

we can use formula

$A_2=\frac{P(6)-P(4)}{6-4}$

now, we can plug values

$A_2=\frac{15(1.4142)^{6}-15(1.4142)^{4}}{6-4}$

$A_2=29.99770$

Average rate of change between 6 years and 8 years:

we can use formula

$A_3=\frac{P(8)-P(6)}{8-6}$

now, we can plug values

$A_3=\frac{15(1.4142)^{8}-15(1.4142)^{6}}{8-6}$

$A_3=59.99425$

now, we will check each options

option-A:

we can see that

$A_3-A_2=30$

So, this is FALSE

option-B:

$A_1=\frac{1}{2}A_2$

So, this is TRUE

option-C:

This is FALSE

option-D:

we got

$A_1=\frac{1}{2}A_2$

so, this is FALSE

5 0

3 years ago