Answer:
broad sense heritability = 0.75
Step-by-step explanation:
Step 1: Variables
phenotypic variation (Vp)
genotype variation (Vg)
environment variation (Ve)
broad sense heritability (H)
Step 2: Formulas:
H = Vg / Vp
Vp = Vg + Ve
Vg = Vp - Ve
Step 3: Given data
Vp = 20
Ve = 5
Step 4: Computation
Vg = 20 - 5 = 15
H = 15 / 20
H = 0.75
Hope this helps!
Answer:
the answer is 16 . the explanation is that because if you have. 200 cm y axis it overcomes the x of other 80
The third one down
Because the best line of fit is a line that goes between the plotted points and it HAS to be a straight line and most of the points close to the line
Answer: 44 miles
WORKINGS
Given,
The distance between Indianapolis and Lima, IL = 173 miles
The distance between Indianapolis and Dayton, ID = 165 miles
The distance between Dayton and Lima, DL is unknown
Since there are straight roads connecting the three cities, the connection between them form a right angles triangle.
The right angle is at Dayton
The hypotenuse is the distance between Indianapolis and Lima, IL
Therefore IL^2 = ID^2 + DL^2
173^2 = 165^2 + DL^2
DL^2 = 173^2 – 165^2
DL^2 = 29929 – 27225
DL^2 = 2704
DL = 52 miles
Therefore, The distance between Dayton and Lima, DL = 52 miles
The question is asking how many more miles would Meg drive if she stopped in Dayton first than if she drove directly to Lima.
That is, Distance of Indianapolis to Dayton + Distance of Dayton to Lima – Direct distance of Indianapolis to Lima
That is, ID + DL – IL
= 165 miles + 52 miles – 173 miles
= 217 miles – 173 miles
= 44 miles
Therefore, Meg would drive 44 more miles if she stopped in Dayton first than if she drove directly to Lima.
