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IRISSAK [1]
3 years ago
5

Suppose the manager of a gas station monitors how many bags of ice he sells daily along with recording the highest temperature e

ach day during the summer. The data are plotted with temperature, in degrees Fahrenheit (°F), as the explanatory variable and the number of ice bags sold that day as the response variable. The least squares regression (LSR) line for the data is ????ˆ=−125.30+2.32???? . On one of the observed days, the temperature was 82 °F and 68 bags of ice were sold. Determine the number of bags of ice predicted to be sold by the LSR line, ????ˆ , when the temperature is 82 °F. Enter your answer as a whole number, rounding if necessary.
Mathematics
1 answer:
Naily [24]3 years ago
7 0
I don’t have the time for my birthday but I’m just asking for a little
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The amount of time that a surveillance camera will run without having to be reset is a random variable having the exponential di
Evgesh-ka [11]

Answer: The required time is 0.743.

Step-by-step explanation:

Since we have given that

\lambda=0.02

We need to find the time above which is 68% of the cameras have to be reset.

So, exponential distribution would be

f(x)=0.02e^{-0.02}

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8 0
4 years ago
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Four thousand nine hundred ninety-nine standard form
marishachu [46]

Answer:

4,999

Step-by-step explanation:

4,999 is the number in standard form, hope this helps!!

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3 years ago
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Question text A savings and loan association needs information concerning the checking account balances of its local customers.
Aliun [14]

Answer:

The lower value for a 98% confidence interval for the true mean checking account balance for local customers is of $451.2.  

Step-by-step explanation:

We have the standard deviation for the sample, which means that the t-distribution is used to solve this question.

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 14 - 1 = 13

98% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 13 degrees of freedom(y-axis) and a confidence level of 1 - \frac{1 - 0.98}{2} = 0.99. So we have T = 2.65

The margin of error is:

M = T\frac{s}{\sqrt{n}} = 2.65\frac{297.29}{\sqrt{14}} = 212.94

In which s is the standard deviation of the sample and n is the size of the sample.

The lower end of the interval is the sample mean subtracted by M. So it is 664.14 - 212.94 = $451.2.

The lower value for a 98% confidence interval for the true mean checking account balance for local customers is of $451.2.  

7 0
3 years ago
Find the range of the given numbers. {41 , 43 , 52 , 25 , 96 , 19 , 72}
vlabodo [156]

Answer: 77

Step-by-step explanation:

$$Find the range of the list:$$(41,43,52,25,96,19,72)$$The range of a list is given by:(largest element) - (smallest element) \\$(41,43,52,25,\bold{96},19,72)$ We see that the largest element is $96:$ $-(($ smallest element $))+96$\\$(41,43,52,25,96,\bold{19},72)$ We see that the smallest element is $19:$ $96-19$\\$$96-19=77$$Therefore, the range of the set is 77

8 0
2 years ago
7m+3mn when m=8 and n=14
svlad2 [7]
Answer: 392
Work:
7×8+3×8×14
56+24×14
56+336
392
8 0
3 years ago
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