Answer:
An expression is shown below:
10n³− 15n² + 20xn² − 30xn
Part A: Rewrite the expression so the GCF is factored completely. (4 points)
10n³− 15n² + 20xn² − 30xn
2*5*n*n*n-5*3*n*n+2*5*2*x*n*n-2*5*3*x*n
<u>Greatest</u><u> </u><u>common</u><u> </u><u>factor</u><u>=</u><u>5</u><u>*</u><u>n</u><u>=</u><u>5</u><u>n</u>
Part B: Rewrite the expression completely factored. Show the steps of your work.
Solution given;
10n³− 15n² + 20xn² − 30xn
5n(2n²-3n+4xn-6x)
5n(2n²+4xn-3n-6x)
5n(2n(n+2x)-3(n+2x))
<u>5n(n+2x)(2n-3</u>)
The distributive property of multiplication is a very useful property that lets you rewrite expressions in which you are multiplying a number by a sum or difference.
Pick any value in the y column of the table. I'm going to pick 81. Divide the value you picked by the previous y value, which in my case would be 9
Dividing the values gives: 81/9 = 9
So the base is 9. We multiply each y value by 9 to get the next y value
Eg: to go from 1/81 to 1/9, we multiply by 9. Same for 1/9 to 1, and so on.
Answer: Choice B) 9
Note: This trick only works because x is increasing by 1 each time
Answer: 1st: -33 2nd: -32 3rd: -31
Step-by-step explanation:
VIEW THE ATTACHED
༼ つ ◕_◕ ༽つ
Answer:
2−49+2+8
Step-by-step explanation:
x2+2x−49X+8
2−49+2+8