I'm guessing your problem is this: y³ - 9y² + y - 9 = 0 right?
In solving this problem, I recommend doing this: y³ - 9y² + y - 9 = 0 Factor out a y² from the first two numbers in the problem: y²(y - 9) + (y - 9) = 0 Separate the parentheses which means y - 9 goes on one side. The y² added a one since it came from the + 1 in the middle of expression. When you're separating parentheses like this you just take the outside numbers and combine them together. Since + 1 came from the outside of the (y - 9) and y² also was sitting on the outside of (y - 9) combine them to make y² + 1. Like this: (y² + 1)(y - 9) = 0 Now separate your two parentheses to two separate problems: (y² + 1) = 0 and (y - 9) = 0 Now you're y² + 1 will equal: y² = -1 y = √-1 <-- This number doesn't exist so it will be an imaginary number (i). If you guys didn't learn that in your class I recommend just leaving it as i for that part. Now solve y - 9 = 0: y = 9 <-- Since we added nine to both sides to get this.
