Ummmm where is it? I dont see 12
see the attached figure to better understand the problem
we know that
1) If angle 1 and angle 2 are complementary angles
then
m∠1+m∠2=
------> equation A
2) If angle 1 and angle 2 are congruent angles
then
m∠1=m∠2 ------> equation B
Substitute equation B in equation A
m∠1+(m∠1)=
2m∠1=
m∠1=
therefore
<u>the answer is</u>
The expression is given by:

So we need to find an equivalent equation for this problem. Then, we will apply some mathematical rules:
Extracting the common factor 1/4, then:

Or extracting the common factor -1/4, then:

So, comparing these solutions with the answers about, there is no any answer that matches.
Answer:
i pretty sure i do not know that answer to be honest
Step-by-step explanation:
i believe this because i dont know anything about this im still lost
Area of right-angled triangle is given by;
Area, A = 1/2 *b*h, Where b=base, h=height
Therefore,
A1 = 1/2bh = 16 in^2
A2 = 1/2 (2b)(2h) = 2bh
Ratio of increase = A2/A1 = {2bh}/(1/2bh} = 4 (the area is increased 4 times)
The,
A2 = 4*16 = 64 in^2
Therefore,
The area is increased by (64-16) = 48 in^2