Answer:
Option (d)
Step-by-step explanation:
From the given table,
Number of members in 1980 (t = 0) were 5400.
With the period of time number of members increased.
Let the number of years after 1980 = x
Therefore, line of best fit will be in the form of y = mx + b
Where b = Initial number of members = 5400
m = Increase in members in every 5 years duration
So the equation will be,
y = mx + 5400
From the given options,
Equation which matches to our equation is,
y = 310.58x + 5400
For the number of members in year 2022,
x = 2022 - 1980 = 42 years
y = 310.58(42) + 5400
y = 18445
Option (d) will be the answer.
A=g
v=⌠g dt
v=gt+C, where C=v initial
v=gt+vi
h=⌠v dt
h=gt^2/2+vit+C, where C=h initial
h=gt^2/2+vit+hi
We are told that vi=42 ft/s, hi=0, and we know g≈-32 ft/s^2 so
h(t)=-16t^2+42t
The ball will hit the ground when h=0 so
-16t^2+42t=0
-2t(8t-21)=0, since t>0
8t-21=0
8t=21
t=21/8
t=2.625 sec
t≈2.6 sec (to nearest tenth of a second)
Answer:
Maybe yawl can help me on this one too because i do not know this.
Step-by-step explanation:
F(x)=-2x2+4x-6
f(0)=-2x2+4x0-6
f(0)=-4+0-6
f(0)=-10
Answer:
0.6848
Step-by-step explanation:
Mean of \hat{p} = 0.453
Answer = 0.453
Standard deviation of \hat{p} :
= \sqrt{\frac{\hat{p}(1-\hat{p})}{n}} = \sqrt{\frac{0.453(1-0.453)}{100}} = 0.0498
Answer = 0.0498
P(0.0453 - 0.05 < p < 0.0453 + 0.05)
On standardising,
= P(\frac{0.0453-0.05-0.0453}{0.0498} <Z<\frac{0.0453+0.05-0.0453}{0.0498})
= P(-1.0044 < Z < 1.0044) = 0.6848
Answer = 0.6848
