Answer:
210
Step-by-step explanation:
Here comes the problem from Combination.
We are being asked to find the number of ways out in which 3 students may sit on 7 seats in a row. Please see that in this case the even can not be repeated.
Let us start with the student one. For him all the 7 seats are available to sit. Hence number of ways for him to sit = 7
Let us see the student second. For him there are only 6 seats available to sit as one seat has already been occupied. Hence number of ways for him to sit = 6
Let us see the student third. For him there are only 5 seats available to sit as two seat has already been occupied. Hence number of ways for him to sit = 5
Hence the total number of ways for three students to be seated will be
7 x 6 x 5
=210
Answer:
4(2x-3)(2x + 3)
Step-by-step explanation:
Here, we want to simplify the given expression
we can have;
16x^2-36
= 4(4x^2 -9)
we can use the difference of two squares
where;
a^2 - b^2 = (a-b)(a + b)
= 4(2x-3)(2x+ 3)
The expression 7•3x is not equal to the expression 21x. You might think that the two expressions are the same since 7x3 is 21 but the first expression is a dot product. This kind of expression includes the magnitude and direction of the vector in an expression, for example, <span>7•3x. The second expression, 21x, expresses only the magnitude and does not include the direction.</span>
Answer:
4/5 of the cattle is left
Step-by-step explanation:
Given,
A farmer sells 2/5 of his cattle
Let "x" be the total number of cattle
Then,
sold = 2 / 5 x
Then,
Remaining = x - 2x / 5
remaining = 3x / 5
He gives 1/3 of the remainder to his son
son = 1 / 3 × 3x / 5
son = x / 5
Then,
Remaining = 3x / 5 - x / 5
Remaining = 4x / 5
Hope this answer helps you :)
Have a great day
Mark brainliest
Thus 4/5 of the cattle is left
