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Shkiper50 [21]
3 years ago
11

Estimate how many times larger 7 x 10^10 is than 13 x 10^8.

Mathematics
2 answers:
Tpy6a [65]3 years ago
4 0
The answer to this equation is A) 50 times larger
Elena L [17]3 years ago
4 0

Answer:- A) is the right answer.7\times10^{10} is 50 times larger than 13\times10^{8}


Explanation:-

To estimate the number of times 7\times10^{10} is larger than 13\times10^{8}

Let 7\times10^{10} is larger than 13\times10^{8}  by n times.

then 7\times10^{10}  =n\times13\times10^{8}

\Rightarrow\ n=\frac{7\times10^{10}}{13\times10^{8}}\\\\\Rightarrow\ n=\frac{7\times10^{10-8}}{13}.......[by\ law\ of\ exponents\ \frac{a^m}{a^n}=a^{m-n}]\\\\\Rightarrow\ n=\frac{7\times10^2}{13}\\\\\Rightarrow\ n=\frac{7\times100}{13}\\\\\Rightarrow\ n=\frac{700}{13}=53.84\approx50

[as 53.84 is near to 50 by rounding off it to the nearest ten it becomes 50]

Thus 7\times10^{10} is 50 times larger than 13\times10^{8}



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Using the proportional relationship equation, the missing values are:

Third row: x = 6 and y = 9

Fourth row: x = 15

<h3>What is a Proportional Relationship?</h3>

A proportional relationship can be described as a relationship between two variables, x and y, that have equivalent ratios. In order words, one variable always equals a constant when multiplied by the other variable.

The constant is called the constant of proportionality which can be represented as k.

Thus, k = y/x.

A proportional relationship between x and y can be represented with the equation, y = kx, where k is the constant of proportionality.

Using the pairs given in the table, (3, 4.5), find the constant of proportionality, k:

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The equation that models the proportional relationship of the values in the table would be: y = 1.5x.

Use the equation to find the rest of  the missing values.

Third row:

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The missing values for the third row would be: x = 6 and y = 9

Fourth row: Substitute y = 2.5 into y = 1.5x to find x

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Missing value in the fourth row will be: x = 15.

Learn more about proportional relationship on:

brainly.com/question/15618632

#SPJ1

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