Question

Hey can you please help me posted picture of question :)

Answer 1

Answer:
The roots of the equation are -4 and -5

Explanation:
The general form of the quadratic equation is:
ax² + bx + c = 0
The given equation is:
3x² + 27x + 60 = 0
By comparison, we could find that:
a = 3
b = 27
c = 60

Now, to get the roots we would use the quadratic formula shown in the attached image.

By substituting, we would find that:
either x = $\frac{-27+ \sqrt{(27)^2-4(3)(60)} }{2(3)} = -4$

or x = $\frac{-27- \sqrt{(27)^2-4(3)(60)} }{2(3)} = -5$

This means that the roots of the equation are -4 and -5

Hope this helps :)

Answer 2

Sorry dont really know :/