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Nataliya [291]
3 years ago
15

Hey can you please help me posted picture of question :)

Mathematics
2 answers:
cupoosta [38]3 years ago
5 0
Answer:
The roots of the equation are -4 and -5

Explanation:
The general form of the quadratic equation is:
ax² + bx + c = 0
The given equation is:
3x² + 27x + 60 = 0
By comparison, we could find that:
a = 3
b = 27
c = 60

Now, to get the roots we would use the quadratic formula shown in the attached image.

By substituting, we would find that:
either x = \frac{-27+ \sqrt{(27)^2-4(3)(60)} }{2(3)}  = -4

or x = \frac{-27- \sqrt{(27)^2-4(3)(60)} }{2(3)} = -5

This means that the roots of the equation are -4 and -5

Hope this helps :)

AysviL [449]3 years ago
4 0
Sorry dont really know :/
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WILL GIVE BRAINLIEST
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Given:

One linear function represented by the table.

Another linear function represented by the graph.

To find:

The greater unit rate and greater y-intercept.

Solution:

Formula for slope (unit rate):

m=\dfrac{y_2-y_1}{x_2-x_1}

From the given table it is clear that the linear function passes through (0,5) and (5,15). The function intersect the y-axis at (0,15), so the y-intercept is 15.

m_1=\dfrac{15-5}{5-0}

m_1=\dfrac{10}{5}

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So, the unit rate of first function is 2.

From the given graph it is clear that the linear function passes through (0,6) and (-4,0). The function intersect the y-axis at (0,6), so the y-intercept is 6.

m_2=\dfrac{0-6}{-4-0}

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So, the unit rate of first function is \dfrac{3}{2}.

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2>\dfrac{3}{2}

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15>6

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