Answer:
Rhombus
Step-by-step explanation:
Rhombus: A quadrilateral with four congruent sides and two pairs of parallel sides.
<h3>Hope it is helpful...</h3>
Let's solve your equation step-by-step.
2.5(6x−4)=10+4(1.5+0.5x)
Step 1: Simplify both sides of the equation.
2.5(6x−4)=10+4(1.5+0.5x)
(2.5)(6x)+(2.5)(−4)=10+(4)(1.5)+(4)(0.5x)(Distribute)
15x+−10=10+6+2x
15x−10=(2x)+(10+6)(Combine Like Terms)
15x−10=2x+16
15x−10=2x+16
Step 2: Subtract 2x from both sides.
15x−10−2x=2x+16−2x
13x−10=16
Step 3: Add 10 to both sides.
13x−10+10=16+10
13x=26
Step 4: Divide both sides by 13.
13x
13
=
26
13
x=2
Answer:
x=2
A+S=589
S=a-61
A+A-61=589
2a=589+61
2a=650
A=325
S=325-61
S=264
Hope this helps
That is correct since the line in T is not straight it would eventually hit the third quadrant
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<u>We are given the equations: </u>
10x = 10
-5x - 8y = 9
Since we don't have a coefficient of y in the first equation, we will rewrite the first equation as:
10x + 0y = 10
<u>Writing an Augmented matrix for the 2 equations:</u>
10x + 0y = 10
-5x - 8y = 9
![\left[\begin{array}{ccc}10&0|&10\\-5&-8|&9\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D10%260%7C%2610%5C%5C-5%26-8%7C%269%5Cend%7Barray%7D%5Cright%5D)
