question 1 is congruent. 2 is not congruent and 3 is congruent
If a semicircle is rotated about the x axis of the graph then the resulting three dimensional shape will be a sphere.
Given a semicircle on a graph.
A semicircle is a half circle .A sphere is a geometrical object that is a three dimensional shape , It is the set of points that are all at the same distance r from given point in three dimensional shape.
Rotation is basically an action of rotating around an object or an axis.
If a semicircle is rotated about x axis then the resulting figure will be a sphere. This is because of the fact that when the semi circle is rotated about the x axis then all the points will be at equal distance in all directions from the center.
Hence if a semicircle is rotated about x axis then the resulting figure will be a sphere.
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Can you post your middle school questions in the middle school area...
9 4/5 - 2 3/10 = X
9 8/10 - 2 3/10 = X
7 5/10 = X
7 1/2 is simplest form
Answer:
Infinite
Step-by-step explanation:
3x+15=2x+10+x+5
grouping
3x+15=3x+15
If you have a equation where both sides are the exactly the same, the solutions are infinite. This is written as: x€ℝ
A <span>counterclockwise rotation of 270º about the origin is equivalent to a </span><span>clockwise rotation of 90º about the origin.
Given a point (4, 5), the x-value, i.e. 4 and the y-value, i.e. 5 are positive, hence the point is in the 1st quadrant of the xy-plane.
A clockwise rotation of </span><span>90º about the origin of a point in the first quadrant of the xy-plane will have its image in the fourth quadrant of the xy-plane. Thus the x-value of the image remains positive but the y-value of the image changes to negative.
Also the x-value and the y-value of the original figure is interchanged.
For example, given a point (a, b) in the first quadrant of the xy-plane, </span><span>a counterclockwise rotation of 270º about the origin which is equivalent to a <span>clockwise rotation of 90º about the origin will result in an image with the coordinate of (b, -a)</span>
Therefore, a </span><span>counterclockwise rotation of 270º about the origin </span><span>of the point (4, 5) will result in an image with the coordinate of (5, -4)</span> (option C)