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Nat2105 [25]
4 years ago
12

Whats the difference between graphing and writing equations from table, points, and equations,

Mathematics
1 answer:
satela [25.4K]4 years ago
5 0
The difference is that a graph is multiple of them and a table is in sections in points it’s like jotting them down and equations is step-by-step

Hope the help:)
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Help !! 10 points!! :)
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Step-by-step explanation:

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Sophia wanted to increase the area of her vegetable garden. She extended the length from 10 feet to 30 feet. How many times larg
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3 times larger

Step-by-step explanation:

10 to 30

is a 300% increase

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For which value of x is the row in the table of values incorrect? the function is the quadratic function y=-1/2x^2
liberstina [14]

Answer:

D. x = 5

Step-by-step explanation:

At x = 5

y = -½(5)²

y = -½ × 25 = -25/2 = -12½

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Lesson 12 practice problem number 2 imath book unit 1 geomitry
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Biologists stocked a lake with 80 fish and estimated the carrying capacity (the maximal population for the fish of that species
kotegsom [21]

Answer:

P(t) = \frac{160000e^{1.36t}}{2000 + 80(e^{1.36t} - 1)}

Step-by-step explanation:

The logistic equation is the following one:

P(t) = \frac{KP(0)e^{rt}}{K + P(0)(e^{rt} - 1)}

In which P(t) is the size of the population after t years, K is the carrying capacity of the population, r is the decimal growth rate of the population and P(0) is the initial population of the lake.

In this problem, we have that:

Biologists stocked a lake with 80 fish and estimated the carrying capacity (the maximal population for the fish of that species in that lake) to be 2,000. This means that P(0) = 80, K = 2000.

The number of fish tripled in the first year. This means that P(1) = 3P(0) = 3(80) = 240.

Using the equation for P(1), that is, P(t) when t = 1, we find the value of r.

P(t) = \frac{KP(0)e^{rt}}{K + P(0)(e^{rt} - 1)}

240 = \frac{2000*80e^{r}}{2000 + 80(e^{r} - 1)}

280*(2000 + 80(e^{r} - 1)) = 160000e^{r}

280*(2000 + 80e^{r} - 80) = 160000e^{r}

280*(1920 + 80e^{r}) = 160000e^{r}

537600 + 22400e^{r} = 160000e^{r}

137600e^{r} = 537600

e^{r} = \frac{537600}{137600}

e^{r} = 3.91

Applying ln to both sides.

\ln{e^{r}} = \ln{3.91}

r = 1.36

This means that the expression for the size of the population after t years is:

P(t) = \frac{160000e^{1.36t}}{2000 + 80(e^{1.36t} - 1)}

4 0
3 years ago
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