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Zielflug [23.3K]
3 years ago
10

In a family,the ages of children arranged from the youngest to the oldest are 2,6,y,14 and z.if the sequence of the ages is in a

n arithmetic progressions what is the ratio z:y​
Mathematics
1 answer:
elena-14-01-66 [18.8K]3 years ago
5 0

Answer:

9/5

Step-by-step explanation:

The common difference = 6 - 2 = 4

The age after 6 is 6 + 4 = 10 = y

The age after 14 is 14 + 4 = 18 = z

z/ y = 18/10 = 9/5

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A two digit number has a tens digit and a ones digit.
Let's say x = tens digit and y = ones digit

"The sum of the digits is 5"
x + y = 5

The next phrase is "the number multiplied by 3 is 42" but we need to represent the number using the digits. So they need to be multiplied first by their place value and added together. [Example: 34 = 3(10) + 4(1)]

The number is: 10x + y
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The system of equations: (two equations for two unknowns)
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30x + 3y = 42

Then you can use substitution or elimination to combine and solve.
I'll use elimination, multiply the entire top equation by -3 and add the equations together. y will cancel out

-3x - 3y = -15
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27x + 0 = 27
x = 1

then plug x = 1 into either equation to find y

1 + y = 5
y = 4

remember the x and y represent digits so the number xy is 14
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