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Zielflug [23.3K]
3 years ago
10

In a family,the ages of children arranged from the youngest to the oldest are 2,6,y,14 and z.if the sequence of the ages is in a

n arithmetic progressions what is the ratio z:y​
Mathematics
1 answer:
elena-14-01-66 [18.8K]3 years ago
5 0

Answer:

9/5

Step-by-step explanation:

The common difference = 6 - 2 = 4

The age after 6 is 6 + 4 = 10 = y

The age after 14 is 14 + 4 = 18 = z

z/ y = 18/10 = 9/5

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Please help me thank you
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Answer:

  • f(4) = -12
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Put the value where the variable is and do the arithmetic.

Personally, I find it easier not to deal with so many minus signs. I would rewrite the function to ...

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_____

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