All categories

3 years ago

Question 2.2. Which ordered pairs make the inequality true?

Mathematics

1 answer:

taurus [48]3 years ago

8 0

<span>Question 2.2. Which ordered pairs make the inequality true?</span><span>2x + y > –4</span>The solutions are (-1, 2) and (1, -5), look at the graph in the attachment.

Question 3.3. What is the slope of the line represented by the equation?

There is no equation

Question 4.4. What is the slope of the line represented by the equation 6x - 3y = 4?

Convert to slope-intercept form:

6x - 3y = 4

Subtract 6x to both sides:

-3y = -6x + 4

Divide -3 to both sides:

y = -6/-3x + 4/-3

Simplify:

y = 2x - 4/3

Now it's in slope intercept form, y = mx + b, where 'm' is the slope. So the slope here is 2.

Question 5.5. What is the simplified form of the expression?

15y - 3(4y + 10)

Distribute -3 into the parenthesis:

15y - 12y - 30

Combine like terms:

3y - 30

You might be interested in

Hard question but would help me out

Alekssandra [29.7K]

Answer:

Critical value f(1)=2.

Minimum at (1,2), function is decreasing for $0$ and increasing for $x>1.$

$\left(3,\dfrac{4}{\sqrt{3}}\right)$ is point of inflection.

When 0<x<3, function is concave upwards and when x>3, , function is concave downwards.

Step-by-step explanation:

1. Find the domain of the function f(x):

$\left\{\begin{array}{l}x\ge 0\\x\neq 0\end{array}\right.\Rightarrow x>0.$

2. Find the derivative f'(x):

$f'(x)=\dfrac{(x+1)'\cdot \sqrt{x}-(x+1)\cdot (\sqrt{x})'}{(\sqrt{x})^2}=\dfrac{\sqrt{x}-\frac{x+1}{2\sqrt{x}}}{x}=\dfrac{2x-x-1}{2x\sqrt{x}}=\dfrac{x-1}{2x^{\frac{3}{2}}}.$

This derivative is equal to 0 at x=1 and is not defined at x=0. Since x=0 is not a point from the domain, the crititcal point is only x=1. The critical value is

$f(1)=\dfrac{1+1}{\sqrt{1}}=2.$

2. For $0$ the derivative f'(x)<0, then the function is decreasing. For $x>1,$ the derivative f'(x)>0, then the function is increasing. This means that point x=1 is point of minimum.

3. Find f''(x):

$f''(x)=\dfrac{(x-1)'\cdot 2x^{\frac{3}{2}}-(x-1)\cdot (2x^{\frac{3}{2}})'}{(2x^{\frac{3}{2}})^2}=$

$=\dfrac{2x^{\frac{3}{2}}-2(x-1)\cdot \frac{3}{2}x^{\frac{1}{2}}}{4x^3}=\dfrac{2x^{\frac{3}{2}}-2\cdot\frac{3}{2}x^{\frac{3}{2}}+ 2\cdot\frac{3}{2}x^{\frac{1}{2}}}{4x^3}=$

$=\dfrac{-x+3}{4x^{\frac{5}{2}}}.$

When f''(x)=0, x=3 and $f(3)=\dfrac{3+1}{\sqrt{3}}=\dfrac{4}{\sqrt{3}}.$

When 0<x<3, f''(x)>0 - function is concave upwards and when x>3, f''(x)>0 - function is concave downwards.

Point $\left(3,\dfrac{4}{\sqrt{3}}\right)$ is point of inflection.

4 0

3 years ago

ILL GIVE BRAINLEST, find the value of x

Elden [556K]

Answer:

x=90 degrees

Step-by-step explanation:

It is a right corner. Please give branliest

6 0

2 years ago

If f(x) = 3x - 2 and g(x) = 2x + 1, find (f+ g)(x).

Leto [7]

The answer would be
5x-1

3 0

3 years ago

at the bake sale connie bought 4 chocolate cookies kevin bought 4 brownies and luis bought 6 sugar cookies in simplest form what

ch4aika [34]

3/7 is the correct awnser as u can see because connie has 4 choclate cookies and kevien bought 4 brownies and luis bought 6 sugar cookies and in the simplest form the fraction would be 3/7.

4 0

3 years ago

Mark’s food for lunch cost $12. The restaurant added a 5 percent sales tax, $0.60, to the bill. Mark wants to pay a 20 percent t

kotykmax [81]

12+.60+ 12.60

12.60*20%

12.60*.20= 2.52

Tip should be around $2.52

Hope this helped :)

7 0

3 years ago

Read 2 more answers