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2 years ago

Which graph represents a proportional relationship .

Mathematics

1 answer:

ZanzabumX [31]2 years ago

3 0

Answer:

Answer choice C

Step-by-step explanation:

This is the only graph which has a linear equation and starts from 0,0.

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4. If A = (-4, -5) and B = (-1, -10), what is the length of segment AB? Round your answer to the nearest hundredth.

HACTEHA [7]

Answer:

5.83095 or √34

Step-by-step explanation:

Find the difference between coordinates:

(x2-x1) = (-1 - -4) = 3

(y2-y1) = (-10 - -5) = -5

Square the results and sum them up:

(3)2 + (-5)2 = 9 + 25 = 34

Now Find the square root and that's your result:

Exact solution: √34 = √34

Approximate solution: 5.831

7 0

2 years ago

What is the sample space for a 5 sided number cube?

grigory [225]

Answer:

{1, 2, 3, 4, 5}

Step-by-step explanation:

Sample space is the set of all possible outcomes. Supposing that the 5 sided number cube has numbers one to five on its sides, the possible outcomes are the numbers that can be rolled, then its sample space is: {1, 2, 3, 4, 5}

3 0

2 years ago

What value of n makes the equation true?

Naddik [55]

Answer:

n = 5.2.

Step-by-step explanation:

-20.8 = -4n

We divide both sides of the equation by -4:

-20.8 / -4 = -4n/-4

5.2 = n (answer).

4 0

2 years ago

Read 2 more answers

What is 350X40= SHOW WORK PLZ HELP ME

Tomtit [17]

2
350
x 40
____
000
1400
____
1,400

8 0

3 years ago

Graph this rational equation. Identify the points of discontinuity, holes, vertical asymptotes, x-intercepts, and horizontal asy

irakobra [83]

Step-by-step explanation:

We have given,

A rational function : f(x) = $\frac{x-2}{x-4}$

W need to find :

Point of discontinuity : - At x = 4, f(x) tends to reach infinity, So we get discontinuity point at x =4.

For no values of x, we get indetermined form (i.e $\frac{0}{0}$ ), Hence there is no holes

Vertical Asymptotes:

Plug y=f(x) = ∞ in f(x) to get vertical asymptote {We can us writing ∞ = $\frac{1}{0}$ }

i.e ∞ = $\frac{x-2}{x-4}$

or $\frac{1}{0}=\frac{x-2}{x-4}$

or x-4 =0

or x=4, Hence at x = 4, f(x) has a vertical asymptote

X -intercept :

Plug f(x)=0 , to get x intercept.

i.e 0 = $\frac{x-2}{x-4}$

or x - 2 =0

or x = 2

Hence at x=2, f(x) has an x intercept

Horizontal asymptote:

Plug x = ∞ in f(x) to get horizontal asymptote.

i.e f(x) = $\frac{x-2}{x-4}$ = $\frac{x(1-\frac{2}{x} )}{x(1-\frac{4}{x} )}$

or f(x) = $\frac{(1-\frac{2}{∞} )}{(1-\frac{4}{∞} )}$

or f(x) = 1 = y

hence at y =f(x) = 1, we get horizontal asymptote

4 0

2 years ago