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Schach [20]
3 years ago
13

How do you solve he formulas for numbers 9 and 10?

Mathematics
1 answer:
Nookie1986 [14]3 years ago
3 0

9)

t = V+K/g, n=multiply both side by g to get :

TG = V+K

 now divide both sides by T to get G alone

 so G = V/t + K/t = g = (V+K)/t


10)l = -a +2S/2

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Whats the vertex at of y-13=2(x+4)^2
Kipish [7]
The vertex form:
y=a(x-h)^2+k
(h,k) - the coordinates of the vertex

y-13=2(x+4)^2 \\
y=2(x+4)^2+13 \\
y=2(x-(-4))^2+13 \\ \\
h=-4 \\ k=13

The coordinates of the vertex are (-4,13).
7 0
3 years ago
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Angles α and β are the two acute angles in a right triangle. Use the relationship between sine and cosine to find the value of β
Dimas [21]

Answer:

From given relation the value of β is 37.5°

Step-by-step explanation:

Given as :

α and β are two acute angles of right triangle

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sin(\frac{x}{2} + 2x) = cos(2x +\frac{3x}{2})

Or, cos(90° - (\frac{x}{2}+2x)) =  cos(2x +\frac{3x}{2})

SO, (90° - (\frac{x}{2}+2x)) = 2x+\frac{3x}{2}

Or, 90° =  2x+\frac{3x}{2} + \frac{x}{2}+2x

or, 90° = \frac{4x}{2} + 4x

Or,  90° =  \frac{12x}{2}

So, x =  \frac{90}{6} = 15°

∴ sin(\frac{x}{2} + 2x) = sin(\frac{15}{2} + 30)

So, sin(\frac{x}{2} + 2x) = sin\frac{75}{2}

∴  The value of Ф_1 = \frac{75}{2} = 37.5°

Similarly  cos(2x +\frac{3x}{2}) =  cos(30 +\frac{45}{2})

So ,The value of Ф_2 = \frac{105}{2} = 52.5°

∵ β   α

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∴ β = 37.5°

Hence From given relation the value of β is 37.5°  Answer

7 0
3 years ago
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dexar [7]

Answer:

B is the answer on edge

Step-by-step explanation:

3 0
3 years ago
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The product of two consecutive positive integers is 56. Find the two integers
vredina [299]

Answer:

Two consecutive integers are of the form

x and x + 1

Their product is equal to 56

x(x + 1) = 56

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Factor and solve

(x - 7)(x + 8) = 0

solutions: x = 7 , x = -8

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Step-by-step explanation:

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2 years ago
Please help what is the equation
Elanso [62]

let us take any two points here (5,20) and (7,30)

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3 years ago
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