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solmaris [256]
4 years ago
10

Help plzzz Thx thx thx

Mathematics
2 answers:
Step2247 [10]4 years ago
7 0
Under 10 the number is 21 because 21+9=30 and the other side is 9
Semenov [28]4 years ago
3 0
9m * 10m + 9m * 30 m

= 9m * ( 10m + 30m)

= 9m * 40m

= 9m * 4 * 10m

= 36m * 10m

= 360 m²

--------

Area:

360 metres²
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Kesha wants to know whether x + 4 is a factor of p(x) = −3x^3 − 15x^2 − 16x −16.
Reika [66]
It's the factor theorem.
P(-4)
Equal to 0
3 0
3 years ago
4) 8(-2 + 2n) + 3n = 40 +5n
Nikitich [7]

Answer:

use the distributive property to distribute the 8

-16+16n+3n=40+5n

-16+19n=40+5n

-16=40+5n-19n

-16=40-14n

-14n+40= -16

-14n= -16-40

-14n= -56

n= -56/-14

n= 4

5 0
3 years ago
Read 2 more answers
Cuanto es (2x+2y=20) (-2x-6y=-52) con método de igualación y método de suma y resta
Nataly_w [17]

x =2       y =8

2x + 2y=20

2x=20-2y

x=10-y

Ahora len la otra ecuacion remplazamos x por (10-y)

-2(10-y)-6y=-52

-20+2y-6y=-52

2y-6y= -32 (-52+20= -32)

-4y=-32

-y=-8

y=8            x=10-y  x=2

2*2+2*8=20

4+16=20

-2*2-6*8= -52

-4-48= -52


6 0
3 years ago
What is tan K? help pleasee
alina1380 [7]

8/15

Hope this helps!

5 0
3 years ago
Read 2 more answers
Need Help! I don't get it
serious [3.7K]
Well hmmm let's say you take the car and go in the city for 60 miles with it, well, the car can do 60 miles per gallon, since you just drove it for 60 miles, you only spent 1 gallon of gasoline then.

that only happens if you drive it for 60 miles, what if you drive it for more, let's do a quick table on that,

\bf \begin{array}{ccll}
miles&cost\\
\text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\
60&3.6(1)\\\\
&3.6\left( \frac{60}{60} \right)\\\\
120&3.6(2)\\\\
&3.6\left( \frac{120}{60} \right)\\\\
180&3.6(3)\\\\
&3.6\left( \frac{180}{60} \right)
\end{array}

and so on, now let's check if you less than 60 miles,

\bf \begin{array}{ccll}
miles&cost\\
\text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\
40&3.6\left( \frac{40}{60} \right)\\\\
20&3.6\left( \frac{20}{60} \right)\\\\
10&3.6\left( \frac{10}{60} \right)
\end{array}

so, if you divide the amount of miles driven, by 60, when you have driven it for 120 miles, 120/60 is just 2, and the cost is for 2 gallons, or 3.6 * 2, which is 7.2 bucks, for 180 miles is 180/60 or 3 gallons for 3.6 * 3 bucks, and so on.

now, what if you drive it instead for "m" miles?

\bf \begin{array}{ccll}
miles&cost\\
\text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\
m&3.6\left( \frac{m}{60} \right)\\\\
\end{array}\implies c=3.6\left( \cfrac{m}{60} \right)\implies c=\cfrac{3.6m}{60}
\\\\\\
c=\cfrac{3.6}{60}m\implies c=0.06m
3 0
3 years ago
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