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NeTakaya
2 years ago
8

Find the GCF of the following monomials. -50m⁴ n⁷ and 40m² n¹⁰

Mathematics
2 answers:
babunello [35]2 years ago
8 0
Greetings!

We can factor this expression/ the GCF is:
-10m^2n^7

(-10m^2n^7)(5m^2-4n^3)

Hope this helps.
-Benjamin
Cerrena [4.2K]2 years ago
7 0

Answer:  10\ m^2\ n^7

Step-by-step explanation:

The given monomials : -50m^4n^7\text{ and }40 m^2 n^{10}

The prime factorization of coefficients :-

50=5\times5\times2\\\\40=5\times2\times2

GCF(50, 40)=2\times5=10

The greatest common degree of m is 2

The greatest common degree of n is 7

So , the GCF of the given monomilas will be :-

10\ m^2\ n^7

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a cube has sides with the following number: 3,3,6,9,,7,8. what is the probability of getting a factor of 9 when rolled?
muminat

Answer:

The probability of rolling a factor of 9 is 1/2, or 50%.

Step-by-step explanation:

The number 9's factors are 1, 3, and 9. Three of the six sides of the cube have a factor of 9. Therefore 3/6 of the sides are factors of nine.

Simplify 3/6 to 1/2 to get a probability of 50%.

5 0
2 years ago
PIPEILY<br> A. 4(3x - 5)<br> 12x - 24
zloy xaker [14]

Answer:

No solution

Step-by-step explanation:

The question is   4(3x-5)=12x-24

so we do the step:12x-20=12x-24

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3 0
3 years ago
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ivann1987 [24]
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3 years ago
If I want to make 12 pillows from the same fabric from 16 yards how much fabric will I use to make each pillow
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4 0
3 years ago
A hog producer is feeding soybean meal and corn to his pigs. He needs to know how many pounds he needs to feed of each in order
Mazyrski [523]

Answer:

Feed 1, Soybean meal required =  \dfrac{2000}{3} \text{ lbs.}

Feed 2, Corn meal required = \dfrac{4000}{3} \text{ lbs.}

Step-by-step explanation:

Total feed is <em>1 ton</em> i.e. <em>2000 lbs</em>.

Let <em>x</em> be the amount of Feed 1 required.

Feed 1 has 45\% of protein.

\text{Protein in Feed 1 = }x \times \dfrac{45}{100} ..... (1)

Then, amount of Feed 2 required = (2000 - x) \text{ lbs.}

Feed 2 has 15\% of protein.

\text{Protein in Feed 2 = }(2000 - x) \times \dfrac{15}{100} ..... (2)

As per question, total protein required is 25\% of 2000 lbs .

Adding (1) and (2) and putting it equal to total protein required.

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Feed 2 required = 2000 - \dfrac{2000}{3}\\

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7 0
3 years ago
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