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klemol [59]
3 years ago
10

Two different chemotherapy regimens can be used for the treatment of breast cancer. The treatment with doxorubicin is known to s

how a remission rate 40% of the time. This treatment costs $1,000. The other treatment, with docetaxel, shows a remission rate 25% of the time and costs $850. The two treatment plans are as follows:
Plan A: Treatment with doxorubicin—if not effective, treatment with docetaxel.
Plan B: Treatment with docetaxel—if not effective, treatment with doxorubicin.
If you are the patient, which statement is the best choice?
A. Based on the probability of overall remission rate, plan A should be selected over plan
B. Based on the probability of overall remission rate, plan B should be selected over plan
C. Based on the cost of the first treatment alone, plan A should be selected over plan B.
D. Based on the overall cost of treatment, plan B should be selected over plan A. E. Based on the probability of survival rate and the cost of treatment, both plans are equivalent, so either can be selected.
Mathematics
1 answer:
trapecia [35]3 years ago
8 0
I think the answer would be C. based on the cost of the treatment alone, plan A should be selected over plan B

If we count the cost and probability of remission, the cost of per 1 % remission with plan A is $ 25 , while the cost of per 1 % remission with plan B is $ 34

hope this helps
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0.7143

- You know the minimum possible grade of the student

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- The answer seems (and is) reasonable. You only created a new lower limit.

Step-by-step explanation:

Distribution Type: Normal

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Range of marks: [78 - 36], [78 + 36]  = [42 to 114]

If you know that a student's grade is greater than 72, what is the probability that it's greater than 84?

In this case, the full probability level is between 72 and the upper limit of 114 (instead of between 42 and 114). First, find the fraction of this probability.

[114 - 72] ÷ [114 - 42]  = 42/72  = 0.5833

So, the probability of a student's mark falling between 72 and 114 is 0.5833.

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What fraction of this interval of 42 will bear marks between 84 and 114?

[114 - 84]  = 30

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