Four friends were born in consecutive years. The sum of their

Mathematics

1 answer:

zimovet [89]2 years ago

4 0

Answer:

Step-by-step explanation:

Since they were born on consecutive years, their ages are 4 consecutive whole numbers. Let the lowest age be x. Then the other ages are x + 1, x + 2, and x + 3.

Now we add the 4 expressions and set the sum equal to 94.

x + x + 1 + x + 2 + x + 3 = 94

4x + 6 = 94

4x = 88

x = 22

The youngest one is 22.

The oldest one is

x + 3 = 22 + 3 = 25

Answer: 25

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