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klemol [59]
2 years ago
7

Four friends were born in consecutive years. The sum of their

Mathematics
1 answer:
zimovet [89]2 years ago
4 0

Answer:

25

Step-by-step explanation:

Since they were born on consecutive years, their ages are 4 consecutive whole numbers. Let the lowest age be x. Then the other ages are x + 1, x + 2, and x + 3.

Now we add the 4 expressions and set the sum equal to 94.

x + x + 1 + x + 2 + x + 3 = 94

4x + 6 = 94

4x = 88

x = 22

The youngest one is 22.

The oldest one is

x + 3 = 22 + 3 = 25

Answer: 25

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Harman [31]

Answer:

f(2) =5

Step-by-step explanation:

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3 years ago
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6 0
3 years ago
1) g=-y+c/x, solve for X
Sindrei [870]

Answer:

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Step-by-step explanation:

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Given problem g=\frac{-y+c}{x}

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g = \frac{x y+c}{x}

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<u>Step 2</u>:-

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taking common 'x' we get,

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<u>Final answer</u>:-

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