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dimulka [17.4K]
3 years ago
7

Jack did 3/5 of all problems on his weekend homework before Sunday. On Sunday he solved 1/3 of what was left and the last 4 prob

lems. How many problems were assigned for the weekend?
Mathematics
1 answer:
Arturiano [62]3 years ago
8 0

Answer:

3/5 + 2/5·1/3 = 11/15

1 - 11/15 = 4/15

4/15 are 4 Problems

1/15 are 1 Problem

15/15 are 15 Problems

15 Problems were assigned for the weekend.

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The average daily attendance at the Lincoln school was 348 students during the month of March. If the month has 21 school days w
lakkis [162]

Answer:

7308

Step-by-step explanation:

348 times 21 = 7308

Sorry if this is wrong.

3 0
3 years ago
!!!!!!!!!!!!Please help!!!!!!!!!!!!!!
aksik [14]

Answer:

The answer to your question is a) (f°g)(x) = 4x² + 2

                                                    b) (f + g)(x) = 4x² + x + 2

                                                    c) (f - g)(-3) = -37

Step-by-step explanation:

Data

f(x) = x + 2

g(x) = 4x²

a) Calculate (f°g)(x)

Just sum the function

(f°g)(x) = (4x²) + 2

-Simplification

(f°g)(x) = 4x² + 2

b) (f + g)(x)

(f + g)(x) = x + 2 + 4x²

-Simplification

(f + g)(x) = 4x² + x + 2

c) (f - g)(-3)

-Calculate (f - g)(x)

(f - g)(x) = x + 2 - 4x²

-Simplify

(f - g)(x) = -4x² + x + 2

-Evaluate in (-3)

(f - g)(-3) = -(4)(-3)² + (-3) + 2

-Simplification

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-Result

(f - g)(-3) = -36 - 3 + 2

(f - g)(-3) = -37

5 0
3 years ago
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7 0
3 years ago
What is the lcm of 13 and 9​
telo118 [61]

Answer:

LCM = 117

Step-by-step explanation:1.  Find the prime factorization of 9. 9 = 3 x 3  2. find the prime factorization of 13. 13 = 13  3. Multiply each factor the greater number of times it occurs in steps 1) or 2) above to find the lcm:   3 x 3 x 13 = 117. Hope it helped.

8 0
3 years ago
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