The answer to this problem is =<span><span><span><span>−9/</span>10</span>x</span>+<span><span>−85/</span><span>6</span></span></span>
15 electricians worked for 24 days to the whole job, now, there are 15 of them, so on any given day, each electrician worked one whole day, in 24 days, that one electrician worked 24 days total.
now, there were 15 electricians on any given day though, since each one of them worked the whole day that one day, so the "days work worth" on a day is 15, so the house gets 15days worth of work because of that.
so how many "days worth" did all 15 do on the 24 days, well, 15+15+15+15+15+15+15+15+15+15+15+15+15+15+15+15+15+15+15+15+15+15+15+15, namely 15 * 24, or 360 days worth of work.
since it takes 360 days worth of work to do the whole wiring, in how many days would 18 electricians do it? 360/18.
Answer:
probability that Caroline buy both CD and fruit = 0.52
Step-by-step explanation:
We have given that the probability of Caroline buys a fruit P = 0.4
So probability of Caroline does not buy the fruit = 1 - 0.4 = 0.6
Probability Caroline buys a CD P = 0.2
So probability of Caroline does not buy the CD = 1 - 0.2 = 0.8
So probability that Caroline does not buy either buy CD or fruit = 0.8×0.6=0.48
So probability that Caroline buy both CD and fruit =1-0.48 = 0.52
